The discussion revolves around calculating the average thrust force required for an airplane to take off, given its take-off speed of 250 mi/h and weight of 110,000 Kg. Participants are exploring the relationship between weight, thrust, and the units of measurement involved.
The conversation is ongoing, with participants providing insights into the definitions of weight and thrust. Some have raised concerns about the clarity of the question and the potential omission of necessary information, such as runway length. There is no explicit consensus on how to proceed with the calculations.
Some participants note that the question may be poorly worded, highlighting the distinction between mass and weight. There is also mention of the possibility that extraneous information is included to complicate the problem.
rabbitweed said:mi/h is miles per hour. Think of it as distance/time, ie, velocity.
W(eight) is a force; it is your mass multiplied by the acceleration of the body you are standing on. On this case it is earth; so acceleration due to g(ravity) = 9.81 m/s.
I hope it is clear then that the Weight force F = mW of the aircraft is
9.81 * 110000 = 1,079,100 N, or 1079 kN.
Which I am pretty sure must be the answer...but to be honest the question is rather poorly written. Is that how it appears at in the textbook/whatever? Planes don't take off vertically because of the horizontal force applied by the Engines, as you probably well already know...
Let me know if there's anything you didn't get or would like clearing up:)
BlueOwl said:where does the 250 miles per hour come into the formula though? or it doesn't ?