Calculating Average Thrust Force for Airplane Take-off

AI Thread Summary
The discussion revolves around calculating the average thrust force for an airplane during take-off, given a take-off speed of 250 mi/h and a weight of 110,000 kg. Participants clarify that the speed is a measure of velocity and that weight is calculated using the formula F = mg, resulting in a weight force of approximately 1,079,100 N. There is confusion regarding the relevance of the take-off speed in the calculation and concerns about the clarity of the question, which incorrectly uses mass instead of weight. The conversation highlights the need for precise wording in physics problems and offers to recommend better resources for study. Overall, the participants emphasize the importance of understanding the concepts of force, weight, and the context of the problem.
BlueOwl
Messages
8
Reaction score
0

Homework Statement



The take-off speed of a given airplane is 250 mi/h. If the take-off weight is 110,000 Kg, what is average the thrust force exerted by the engines?


Homework Equations



w=mg ,F=ma , F=mW

The Attempt at a Solution



the mi/h confuses me and I don't know which formula to use and is the average thrust force the net force?
 
Physics news on Phys.org
mi/h is miles per hour. Think of it as distance/time, ie, velocity.

W(eight) is a force; it is your mass multiplied by the acceleration of the body you are standing on. On this case it is earth; so acceleration due to g(ravity) = 9.81 m/s.

I hope it is clear then that the Weight force F = mW of the aircraft is

9.81 * 110000 = 1,079,100 N, or 1079 kN.

Which I am pretty sure must be the answer...but to be honest the question is rather poorly written. Is that how it appears at in the textbook/whatever? Planes don't take off vertically because of the horizontal force applied by the Engines, as you probably well already know...

Let me know if there's anything you didn't get or would like clearing up:)
 
rabbitweed said:
mi/h is miles per hour. Think of it as distance/time, ie, velocity.

W(eight) is a force; it is your mass multiplied by the acceleration of the body you are standing on. On this case it is earth; so acceleration due to g(ravity) = 9.81 m/s.

I hope it is clear then that the Weight force F = mW of the aircraft is

9.81 * 110000 = 1,079,100 N, or 1079 kN.

Which I am pretty sure must be the answer...but to be honest the question is rather poorly written. Is that how it appears at in the textbook/whatever? Planes don't take off vertically because of the horizontal force applied by the Engines, as you probably well already know...

Let me know if there's anything you didn't get or would like clearing up:)

where does the 250 miles per hour come into the formula though? or it doesn't ?
 
I suspect that you left out some info? Perhaps the length of the runway?

And this certainly is a poorly worded question. For instance, kg is a unit of mass, not weight. If this is verbatim out of your physics book, then I feel sorry for you, and I hope we can be of some service.
 
BlueOwl said:
where does the 250 miles per hour come into the formula though? or it doesn't ?

It doesn't seem to at all. This is rather common in physics questions; give you quantities you don't need to confuse you. But with that question it really is hard to tell what on Earth they're asking.

Can I ask; are you doing this for school, or self-study? If the latter I'd be happy to recommend a good textbook.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top