Calculating Centripetal Acceleration of Space Telescope in Orbit

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SUMMARY

The discussion focuses on calculating the centripetal acceleration of a space telescope in a stable circular orbit. The telescope has a mass of 10,000 kg and orbits at an altitude of 3630 km above the Earth's surface. The correct formula for centripetal acceleration is derived from Newton's law of gravitation, resulting in an expected value of 4.0 m/s². A common error identified is the failure to convert the Earth's radius from kilometers to meters, which leads to incorrect calculations.

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I've done a bunch of these before, but don't know why I'm not getting the right answer this time around:

A space telescope of mass m[t]=10,000 kg is in a stable circular orbit above the Earth at an altitude h=3630 km. The radius and mass of the Earth are R[e]=6370 and M[e]=6x10^24 kg. Newtons gravitational constant is 6.672x10^-11.

What is the acceleration of the space telescope as it orbits the earth?

_____________

So this is simple enough-we're looking for the centripetal acceleration. So m[t]*Ac=GM[e]m[t]/R^2[earth center to satellite]. The m[t]'s cancel out, so we have centripetal acceleration =GM[e]/R^2, and I'm getting a really large number, even though the answer is supposed to be 4.0 m/s^2. What do you see I'm doing wrong?
 
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R[e] is in km, did you convert it meters?
 

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