# Calculating Clebsch Gordon Coefficients

1. Mar 28, 2010

### quasar_4

1. The problem statement, all variables and given/known data

Find the Clebsch Gordon coefficients of $$1/2 \otimes 1 = 3/2 \oplus 1/2$$

2. Relevant equations

We have some properties of the CG coefficients which might be useful:

1) they are nonzero only if j is between j1-j2 and j1+j2
2) m = m1+m2 for nonzero coefficients
3) they are real

3. The attempt at a solution

I am horribly confused. I know that the CG coefficients are given as the coefficients in the expansion

$$|j m, j_1 j_2 \rangle = \sum_{m_1} \sum_{m_2} | j_1 m_1, j_2 m_2 \rangle \langle j_1 m_1, j_2 m_2| jm, j_1 j_2\rangle$$

or

$$\langle j_1 m_1, j_2 m_2 | j m \rangle$$

and I know that the possible |j m j1 j2> states are for the product space with j1 = 1, j2 = 1/2:

$$| \frac{3}{2} \frac{3}{2} ,1 \frac{1}{2} \rangle, | \frac{3}{2} \frac{1}{2},1 \frac{1}{2} \rangle, | \frac{3}{2} \frac{-1}{2} ,1 \frac{1}{2} \rangle, | \frac{3}{2}\frac{-3}{2} ,1 \frac{1}{2} \rangle, | \frac{1}{2} \frac{1}{2} ,1 \frac{1}{2} \rangle, | \frac{1}{2} \frac{-1}{2} ,1 \frac{1}{2} \rangle$$

but I don't understand what on earth to do or where to even start. Any help would be great.

2. Mar 28, 2010

### nickjer

You usually just look them up in a table. I hope your assignment doesn't want you to actually derive them. Also, I am a bit confused on your notation in the first sentence.

3. Mar 28, 2010

### quasar_4

Yes, I think the notation is what's confusing me. I computed some of the coefficients a couple of years ago in an undergraduate class, but I've never seen this notation. I guess what the author means is to find the coefficients for all the basis kets in the product space where j1 = 1/2, j2 =1. There are (2*j1+1)*(2j2+1)=6 such kets.

I actually have figured it out - but boy, I think Shankar has weird notation... :yuck:

All one needs do is to start with the maximal possible z component, and apply lowering operators for each given j value, along with applying orthogonality and normalization conditions. A bit tricky but doable...

4. Mar 28, 2010

### vela

Staff Emeritus
Start with the $| 3/2\mbox{ }3/2 \rangle$ state. You know that it has to correspond to $|1/2\mbox{ }1/2; 1\mbox{ }1\rangle$. Then apply the lowering operator to get $| 3/2\mbox{ }1/2 \rangle$, and so on.

Edit: Oh sure, figure it out right before I post! ;)

5. Mar 28, 2010

### quasar_4

Thanks anyway! It's good to know that my solution wasn't just pure nonsense :-)