Calculating Cumulative Time Changes over 20 Centuries

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SUMMARY

The cumulative effect of a uniform increase in the length of the day by 0.0010 seconds per century results in a total increase of 2.1 hours over 20 centuries. The calculation involves determining the average increase in length per day, which is 0.0001 seconds, and multiplying this by the total number of days in 20 centuries. This leads to the conclusion that the initial assumption of simply multiplying the increase by the number of centuries was incorrect, as it does not account for the cumulative nature of daily increases.

PREREQUISITES
  • Understanding of basic time measurement concepts
  • Familiarity with cumulative calculations
  • Knowledge of the number of days in a century (365.25 days accounting for leap years)
  • Basic arithmetic operations
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  • Calculate the total number of days in 20 centuries
  • Learn about cumulative effects in time measurement
  • Explore the implications of time dilation in physics
  • Investigate historical changes in the length of the day
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Mathematicians, physicists, educators, and anyone interested in the implications of time measurement and its historical changes.

Fletcher
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The exercise:

Assuming the length of the day uniformly increases by 0.0010s per century, calculate the cumulative effect on the measure of time over 20 centuries.

The answer given in the book:

2.1 hours

My initial thought was 0.001 x 20, but that's apparently wrong. I think I'm missing something basic.
 
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Everyday it increases uniformly by .001s per century so in one century each day will be .0001s longer. How much total time does this add on in 20 centuries?
 
Fletcher said:
My initial thought was 0.001 x 20, but that's apparently wrong. I think I'm missing something basic.
What you calculated is the increased length of a single day after 20 centuries. What's the average increase per day? How many days in 20 centuries?
 

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