Calculating Echo Time: 245 Hz Sound Frequency in a 1.41 m Wavelength Canyon

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Homework Help Overview

The problem involves calculating the time it takes for an echo of a sound wave to return after being projected into a canyon. The sound has a frequency of 245 Hz and a wavelength of 1.41 m, with the canyon being 1.50 km long.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between frequency, wavelength, and wave speed. There is an inquiry into how to calculate the time taken for the echo based on the distance and speed of the wave.

Discussion Status

Some participants have provided calculations for wave speed and have begun to apply the formula for time based on distance and speed. There is an indication of agreement on the calculations presented, but no explicit consensus on the final answer.

Contextual Notes

The discussion includes assumptions about the sound wave traveling in a straight line and the conditions of the canyon, but specific details about environmental factors are not provided.

Brittykitty
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A 245 Hz sound with a wavelength of 1.41 m is projected into a narrow canyon. If the canyon is 1.50 km long, what time does it take an echo to be heard?

How would I solve for this question? :)
 
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Given the frequency and wavelength, what is the speed of your wave?
 
245[hz] * 1.41[m] = 345 m/s? :)
 
Brittykitty said:
245[hz] * 1.41[m] = 345 m/s? :)

Right, so the wave must travel 1.5 km while traveling at 345 m/s, how would you find the time taken given the distance traveled and the speed?
 
t=d/s
t=1.5km/ 345ms?
t=4.35s?
 
Yes that should be it.
 
Thank you SO much! :D
 

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