Calculating Energy of Two Masses on a Spring

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SUMMARY

The discussion focuses on calculating the energy of a macroscopic oscillator consisting of two equal masses attached to a spring, oscillating with amplitude A at frequency v. The user assumes a frictionless environment and derives the position and velocity equations using classical physics principles. The maximum velocity is determined, leading to an energy calculation of the spring. However, feedback suggests that the user should consider the relative motion of both masses and utilize a free body diagram to solve the differential equations governing their motion.

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Homework Statement


Consider the following macroscopic oscillator: Two masses of equal mass are attached to a spring and oscillate with amplitude A at frequency v. Use classical physics to calculate the energy of the oscillator.


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The Attempt at a Solution


This question doesn't say much about where the mass is attached or what environment this oscillator is in so I assumed that we're in a friction-less environment and the mass is attached on either end of the spring. Please tell me if that is incorrect.
Based on that assumption, I know that the position of one of the mass would travel in a cosine curve. So we have p(t)=A*cos(2*pi*v*x). I can take the derivative of this to get the velocity v(t)=-2*pi*A*v*sin(2*pi*v*x). The maximum velocity is when t=1/(4v). Let's call this new velocity V. Now the energy of the spring should be 2*((1/2)*m*V^2). Is this correct? Or is there another way to do it.

Thanks in advance!
 
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I assumed that we're in a friction-less environment and the mass is attached on either end of the spring. Please tell me if that is incorrect.
You should verify the assumption ... but it is what I'd do.

What you seem to have done is considered the motion of just one mass, assuming the other one is stationary.

The force on the masses depends on their relative positions - so you'd work out the free body diagram and solve the resulting differential equation.

If their motion is antisymmetric with the same amplitude, then you can simplify the problem quite a lot.
 

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