MHB Calculating Exponents for Business Model

  • Thread starter Thread starter DesperatelyLost
  • Start date Start date
  • Tags Tags
    Business Exponents
AI Thread Summary
The discussion focuses on calculating a series of exponential expressions for a business model, specifically using the formula 280 * 0.985^n for n values ranging from 1 to 11. The user seeks a more efficient way to compute these values in a spreadsheet, expressing frustration over the cumbersome nature of writing out each calculation individually. Suggestions include using a general formula and leveraging spreadsheet functions to automate the calculations. It is emphasized that each subsequent value can be derived by multiplying the previous result by 0.985. The conversation highlights the importance of simplifying calculations for business applications.
DesperatelyLost
Messages
2
Reaction score
0
Hi, Everyone.

I suspect I am a bit unique here. I'm struggling with a math problem for a business model rather than a homework assignment. It's been quite a while since I have worked with exponents and I am hoping someone can assist me with a question.

I have the following calculations:
280*.985^11
280*.985^10
280*.985^9
280*.985^8
280*.985^7
280*.985^6
280*.985^5
280*.985^4
280*.985^3
280*.985^2
280*.985^1

The base and coefficient are the same, but the exponent is not. I know that I can't add the exponents because they are not like terms. Is there a way to simplify this into one formula or do I need to calculate each one independently?

Thank you in advance for your assistance!
 
Mathematics news on Phys.org
use a capable calculator or a spreadsheet ...
 

Attachments

  • expfunction.png
    expfunction.png
    432 bytes · Views: 120
  • exp_table1.png
    exp_table1.png
    620 bytes · Views: 109
  • exp_table2.png
    exp_table2.png
    551 bytes · Views: 107
I'm already using a spreadsheet, but it's cumbersome to write out that large of a formula.
 
DesperatelyLost said:
I'm already using a spreadsheet, but it's cumbersome to write out that large of a formula.

I'm not a spreadsheet expert, so you'll probably need to research how to evaluate a function with multiple inputs on one ... or wait until someone with the necessary expertise posts a reply.
 
"280*.985^11
280*.985^10
280*.985^9
280*.985^8
280*.985^7
280*.985^6"

Cell A1: Enter 280
Cell A2: Enter 0.985
Cell A3: Enter 0
Cell A4: Enter =A3+1
Cells A5-A100: Copy the contents of A4 and paste
Cell B3: =A[dollar sign]1*A[dollar sign]2^A3
Cells B4-B100: Copy the contents of B3 and paste

It's upside down from your design, but small changes will solve that problem.
 
I'm not sure what you are looking for.
The general formula is 280*.985^n.
Each next value can be found by multiplying the previous value by .985,
Or alternatively each value can be found by the general formula.
Can you clarify what you are looking for?
 
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Back
Top