Calculating Flight Direction & Velocity: Bush Pilot Flying 250.0 km [N30.0°E]

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SUMMARY

The discussion focuses on a bush pilot's navigation challenge to reach a lake located 250.0 km at a bearing of N30.0°E, while contending with a westward wind of 40.0 km/h and an airspeed of 210.0 km/h. The pilot initially attempted to calculate the necessary heading using the formula sin^-1(40/210), but recognized that this approach is insufficient for the specific destination bearing. The need for a more accurate vector analysis and diagrammatic representation is emphasized to determine the correct heading and ground velocity.

PREREQUISITES
  • Understanding of vector addition in navigation
  • Familiarity with trigonometric functions and their applications
  • Knowledge of airspeed versus ground speed concepts
  • Ability to interpret navigational bearings and angles
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  • Learn how to calculate wind correction angles for flight paths
  • Explore the use of diagrams in solving navigation problems
  • Investigate the effects of wind on ground speed and heading
USEFUL FOR

Aviation students, bush pilots, flight planners, and anyone interested in navigation techniques under wind influence will benefit from this discussion.

malcomfred
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A bush pilot wants to fly her plane to a lake that is 250.0 km [N30.0°E] from her starting point. The plane has an air speed of 210.0 km/h and a wind is blowing from the west at 40.0 km/h.

a) In what direction should she head the plane to fly in directly to the lake?
After determining Vpa, Vag I tried heading = sin^-1 (40/210) = 20, but i think that would only work if it was just 250.0 km instead on 250.0 km [N30.0°E].



b) If she uses the heading determined in (a), what will be her velocity relative to the ground?
no idea since i can't get a.
 
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Why don't you draw a diagram?
 
There is my diagram but I'm not sure if it is right.
 

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