Calculating Force from Two Circular Rings | Exam Prep

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SUMMARY

The discussion centers on calculating the force between two circular rings, each with a radius of 25.0 cm and carrying a current of 3.0 A, separated by 0.10 cm. The magnetic field generated by one ring can be calculated using the formula B = μ₀I / (2πr). The force on one ring due to the other can be derived from F = IL × B, where L is the length of the wire segment. The participants express a need for a solution that avoids integrating around the entire circle.

PREREQUISITES
  • Understanding of magnetic fields generated by current-carrying conductors
  • Familiarity with the Biot-Savart Law
  • Knowledge of vector cross products in physics
  • Basic principles of electromagnetism
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  • Review the Biot-Savart Law for calculating magnetic fields
  • Study vector cross product applications in electromagnetism
  • Explore alternative methods for calculating forces between current loops
  • Practice problems involving magnetic forces between multiple conductors
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Students preparing for physics exams, particularly those focusing on electromagnetism and magnetic forces, as well as educators seeking to clarify concepts related to current-carrying loops.

dangish
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Consider two circular rings, each of radius R = 25.0 cm ,
separated by 0.10 cm as shown. Each ring carries a current
I = 3.0 A. What is the magnitude of the force exerted on one ring by
the other ring?

is there any way to do this without integrating around the whole circle??

I have an exam tomorrow and some advice would be greatly appreciated.
 
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i tried using B=u0I/2Pi*r to get the magnetic field, then using F = ILxB to get force on one ring to another, but I don't think Its right
 

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