Calculating Frequency of Absorbed Electromagnetic Radiation in Bohr Atom

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Discussion Overview

The discussion focuses on calculating the frequency of absorbed electromagnetic radiation in a Bohr atom when an electron transitions between energy levels. It involves theoretical concepts and mathematical reasoning related to quantum mechanics.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant presents the formula for the energy of an electron in a Bohr atom and seeks guidance on calculating the frequency of absorbed radiation during an electron transition from n = 4 to n = 9.
  • Another participant suggests calculating the energy difference between the two levels first and then relating that to frequency using a formula involving Planck's constant.
  • A third participant provides a specific equation for energy difference and photon energy, indicating a relationship between energy and frequency.
  • One participant describes their process of plugging in values, performing subtraction, and dividing by Planck's constant, seeking confirmation of their method.
  • Another participant confirms that the described approach is correct.
  • Additional participants express enthusiasm about the learning process and report successfully obtaining an answer.

Areas of Agreement / Disagreement

Participants generally agree on the steps to calculate the frequency, with no significant disagreements noted in the provided responses.

Contextual Notes

Some assumptions about the applicability of the formulas and constants used may not be explicitly stated, and the discussion does not delve into potential limitations of the Bohr model in explaining atomic behavior.

Who May Find This Useful

Students studying quantum mechanics, particularly those learning about the Bohr model and energy transitions in atoms.

GLprincess02
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The energy (in joules) of an electron energy level in the Bohr atom is given by the expression: [tex]E_{n}[/tex]= -2.179 x [tex]10^-18/n^2 J[/tex]where n is the principal quantum number for the energy level. What is the frequency in Hz of the electromagnetic radiation absorbed when an electron is raised up from level with n = 4 to that with n = 9?

I'm unsure of the the formula to use, or even the first step. Any ideas??
 
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First use your formula to calculate the energy difference between the two levels. Second, relate that to frequency. Look in your book for the formula giving energy of a photon (hint: it involves Planck's constant). You can show us what you get if you still have questions.
 
use the equation [tex]\Delta E = R_{H}^{*} (\frac{1}{n_{f}^{2}} - \frac{1}{n_{i}^{2}}) = hv[/tex]
 
Ok, so I plugged both of the numbers (4 and 9) into the equation. Then I subtracted answer #1 from answer #2. Then I divided this number by h (6.626E-34). Am I doing this correctly?
 
Yes, exactly.
 
this is great!, I could learn something here...
 
Great I got the answer, thanks for all the help!
 

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