Find friction force and coefficient for 5.0-kg block with 43.0 N applied force

[jayyafeelme]

Homework Statement

A force of 43.0 N accelerates a 5.0-kg block at 6.1 m/s2 along a horizontal surface.
How large is the frictional force?

What is the coefficient of friction?

Homework Equations

F = ukFn

The Attempt at a Solution

Fthrust = Ffriction = ukFn = ukFg = uk x m x g = ? x 5.0 kg x 6.1 m/s/s

 

[jayyafeelme]

no one can help me?

 

[jayyafeelme]

bump. i need help please

 

[borgwal]

What's the total force on the block?

 

[jayyafeelme]

43 N i think. that's all the givens i have

 

[borgwal]

No, you clearly have more "givens." And 43 N is NOT the total force.

 

[Garicup]

here the net force of the system is ma

take the forces, -------->u have the applied force...(43N) and the force against it which u don't have (Ff) and equate it to the net force

so, ma = Fapplied - Ffriction

i thinks that's how u solve it...i can be wrong...

once you solve for friction force, you can easily solve for mu by with Ff = muFn

 

[borgwal]

Yes, that's how you solve it, but it gives a bit too much information. The poster has to do some work too!