The discussion focuses on calculating heat loss through a 1m square pane of 6 mm thick glass with a temperature difference of 15°C. The thermal conductivity of glass is specified as k = 0.72 W m-1 K-1. The formula for heat loss is given as Rate of loss of heat = 0.72 W m-1 K-1 x 1 m2 x 15°C / (6 x 10-3 m). The confusion arises regarding the conversion of 6 mm to meters, which is essential for accurate calculations.
PREREQUISITESStudents in physics or engineering, professionals in building design, and anyone interested in understanding heat transfer through materials.
luigihs said:
Determine the heat loss through a 1m square pane of 6 mm thick glass for a temperature difference of 15oC.
Thermal conductivity of glass is k = 0.72 W m^-1 K^-1
Solution
Rate of loss of heat = 0.72W m^-1 K^-1 x 1 m^2 x 15oC/(6x10^-3 m ) <--- Ok so I understand everything but I don't understand where my teacher gets 6x10^-3 ?? is not in the question that number.
Please help me
gneill said:What is 6mm in meters?