Calculating Horizontal Distance and Time for a Package Ejected from a Plane

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Homework Help Overview

The discussion revolves around a physics problem involving the calculation of the time it takes for a package to reach sea level after being ejected from a plane, as well as determining the horizontal distance required for the package to land on an island. The problem is situated within the context of projectile motion and kinematics.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the initial conditions of the problem, including the horizontal velocity of the package and the altitude from which it is ejected. There are attempts to calculate the time of descent and the horizontal distance using kinematic equations. Some participants question the accuracy of the initial velocity conversion and the altitude provided.

Discussion Status

The discussion is ongoing, with participants providing feedback on the calculations presented. There is acknowledgment of a potential error in the initial velocity stated, and a participant has clarified the altitude, which may influence the calculations. Guidance has been offered to re-evaluate the calculations with the corrected values.

Contextual Notes

There is a noted lack of explicit information regarding the acceleration due to gravity or any other forces acting on the package during its descent, which may affect the calculations. Additionally, the original poster's confusion regarding the initial velocity conversion and the altitude may impact the problem-solving process.

tater08
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Homework Statement


After a package is ejected from the plane, how long will it take for it to reach sea level from the time it is ejected? Assume that the package, like the plane, has an initial velocity of 220 mph in the horizontal direction.

If the package is to land right on the island, at what horizontal distance D from the plane to the island should the package be released?


2. Homework Equations

X=Vix *T + 0.5 *at^2 = X=Vix*T
Vfx=Vix+a*t
Vfx^2=Vix^2 + 2*a*x

y=vi*t+0.5a*t^2
Vf=Vi+a*t
vfy^2=Viy^2+2a*y

The Attempt at a Solution



I ended solving for the first part that is looking fro time which was 12.8 sec. For the second part, i converted the 200 mph into 89.41 m/s. I then used the X=Vi *t equation. X=89.41 m/s * 12.78sec = 1142.67 m. But somehow it is the wrong answer. I do not know where else to go. Please help! Thanks
 
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tater08 said:

Homework Statement


After a package is ejected from the plane, how long will it take for it to reach sea level from the time it is ejected? Assume that the package, like the plane, has an initial velocity of 220 mph in the horizontal direction.

If the package is to land right on the island, at what horizontal distance D from the plane to the island should the package be released?


2. Homework Equations

X=Vix *T + 0.5 *at^2 = X=Vix*T
Vfx=Vix+a*t
Vfx^2=Vix^2 + 2*a*x

y=vi*t+0.5a*t^2
Vf=Vi+a*t
vfy^2=Viy^2+2a*y

The Attempt at a Solution



I ended solving for the first part that is looking fro time which was 12.8 sec. For the second part, i converted the 200 mph into 89.41 m/s. I then used the X=Vi *t equation. X=89.41 m/s * 12.78sec = 1142.67 m. But somehow it is the wrong answer. I do not know where else to go. Please help! Thanks


Your original problem says 220 mph not 200 mph.

Your altitude is not given.
 
oops my bad, the altitude is 800 meters and the new x in meters is 1256 meters. sorry about the mixup
 
tater08 said:
oops my bad, the altitude is 800 meters and the new x in meters is 1256 meters. sorry about the mixup

Plug in your new numbers. That's probably all it is.

Good Luck.
 

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