Hello, I just want to make sure that my calculations are correct before doing an experiment. I need to dilute 250ml of 1.5M Cu(NO3)2 to 0.5M and distilled water is to be used as the solvent. So I'm not sure how much (volume) of distilled water need to be added. I used the equation C1xV1=C2xV2 where C1=1.5M V1=250mL C2=0.5M V2=? so 1.5x250=0.5xV2 V2=750mL I'm not sure if I'm doing it right because I'm not sure if the 750mL is the volume of the solvent that is to be added to the 250mL of Cu(NO3)2 to make the concentration 0.5M or if 750mL is the final volume of the Cu(NO3)2... I really need to know how to change the concentration, any help would be greatly appreciated please?