Why doesn't kinetic energy at perihelion equal half the potential energy magnitude?

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klarge
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Given:
Planet is orbiting a star
G = 6.67259 x 10^-11 Nm^2/kg^2
Mstar = 1.99 x 10^30 kg
mplanet = 5.98 x 10^24 kg
distance from perihelion to star = 1.69 x 10^11 m
distance from aphelion to star = 1.745 x 10^11 m
potential energy at perihelion = -4.698 x 10^33 J


Need:
Kinetic energy at perihelion

To solve for perihelion kinetic energy I used GMm/2r and checked it with -.5 x potential energy, but apparently this was incorrect as my answer (2.3493 x 10^33 J) was incorrect.

Am I missing something? Or could the "correct" answer be incorrect (this has been known to occur).
 
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klarge said:
To solve for perihelion kinetic energy I used GMm/2r and checked it with -.5 x potential energy, but apparently this was incorrect as my answer (2.3493 x 10^33 J) was incorrect.
The total energy is [tex]E=-\frac {GMm}{2a}[/tex], not [tex]-\frac {GMm}{2r}[/tex]. The latter equation (the one you used) is only valid for circular orbits.