Calculating Loss Tangent and Poynting Vector for Electromagnetic Waves

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SUMMARY

This discussion focuses on calculating the loss tangent and Poynting vector for electromagnetic waves in a medium with conductivity. The loss tangent is determined using the formula sigma/(omega*epsilon), yielding a numerical value based on the given complex electric field amplitude E(z)/E(0) = 0.3 - j0.4. Additionally, the discussion addresses the calculation of the complex electric field amplitude E(z) and the Poynting vector for circularly polarized waves reflected off a perfect planar mirror.

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  • Understanding of electromagnetic wave theory
  • Familiarity with complex numbers and their applications in physics
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  • Proficiency in using equations for phase and group velocity
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unstoppable
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Hi can someone help me out with these questions? I would greatly appreciate it!

1) A source of unidirection plane waves operates within a medium with moderate conductivity sigma. Suppose we measure the complex electric field amplitudes at the source and at some distance z and find that E(z)/E(0)-0.3-j0.4.
(a) Calculate the loss tangent sigma/(omega*epsilon) of the medium. (Give a numerical value)

(b) What is the ratio of complex magnetic field amplitudes H(z)/H(0) for the same z?




2) A perfect planar mirror in the xy-plane has normally incident and reflected electromagnetic plane waves in the vacuum region z<0 in front of it, at frequency omega. The magnetic field at the mirror surface is circularly polarized:H=H(x + jy)
(x and y are the unit vectors along x and y).

(a) Find the complex electric field amplitude E(z) in the space z<0.
(b) Find the complex Poynting vector(give magnitude and direction) in the space z<0.






2. Homework Equations

equation for phase velocity: Vp=Vp(omega)=omega/k= c*omega/squarerootof(omega^2-omega^2) Note: The second omega^2 is the cuttoff frequency


equation for group velocity: Vg=Vg(omega)=c*squarerootof(omega^2-omega^2)/(omega)
Note: The second omega^2 is the cuttoff frequency.


c=the speed of light 3 X 10^8 m/s


Circular Polarization: E(0)=Eox=1/2Eo(x+jy) +1/2Eo=(x-jy)
Note: j=the imaginary complex number
E(z)=1/2*Eo(x+jy)*e^-j(ko+K)z+1/2*Eo(x-jy)*e^-j(ko-K)z

Poynting Vector: The Vector E X H is the Poynting Vector. It gives the power per unit area that flows at a point;


Loss Tangent:Theta/(omega*epsilon)
 
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Hi unstoppable! :smile:

(have a theta: θ and an omega: ω and an epsilon: ε :smile:)

Show us what you've tried, and where you're stuck, and then we'll know how to help. :wink:
 

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