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## Homework Statement

what is the mass of alum that can be prepared from 1.340g of Al.

## Homework Equations

2Al+2KOH+4H2SO4+22H2O ---> 3H2 + 2KAl(SO4)2 * 12H2O

## The Attempt at a Solution

given Al is the limiting reagent. Find the moles of Al using n=m/M

I find Al moles to be 0.049662mol.

Now multiply this by the molar ratio of 2/2 (which is 1) to find the moles of alum produced.

now calculate for the mass, m = nM. The molar mass of alum is 474.3g/mol. I find the mass of alum to be 23.55g.

Am I right?