- #1

rachelmaddiee

- 67

- 5

- Homework Statement
- I have a question

- Relevant Equations
- N/A

Here is my work** Can someone please tell me if this is correct?

mass = 27.8 g CaCI2

Number of CaCI2 in the compound = (unknown)

Number of CI- ions in the compound = (unknown)

Number of moles = mass/molar mass

To find the number of moles of CaCI2 first you find the molar mass of the compound.

1 mole Ca x 40.08 g Ca/1 mole Ca = 40.08 g

1 mole CI x 30.45 g CI/1 mole CI = 30.45 g

1 mole CI x 30.45 g CI/1 mole CI = 30.45 g

molar mass = (40.08 g + 35.45 g + 35.45 g) = 110.98 g/mol CaCI2

27.8 g CaCI2 x 1 mol CaCI2/110.98 g CaCI2 = 0.250 mol CaCI2

Now from equation No of Chloride ions are : 6.02 x 10^23 x 2 CI- ions =

1.204 x 10^23 CI- ions

mass = 27.8 g CaCI2

Number of CaCI2 in the compound = (unknown)

Number of CI- ions in the compound = (unknown)

Number of moles = mass/molar mass

To find the number of moles of CaCI2 first you find the molar mass of the compound.

1 mole Ca x 40.08 g Ca/1 mole Ca = 40.08 g

1 mole CI x 30.45 g CI/1 mole CI = 30.45 g

1 mole CI x 30.45 g CI/1 mole CI = 30.45 g

molar mass = (40.08 g + 35.45 g + 35.45 g) = 110.98 g/mol CaCI2

27.8 g CaCI2 x 1 mol CaCI2/110.98 g CaCI2 = 0.250 mol CaCI2

Now from equation No of Chloride ions are : 6.02 x 10^23 x 2 CI- ions =

1.204 x 10^23 CI- ions