# Calculating Number of Moles & Ions in CaCI2

• Chemistry
In summary, this student has difficulty with basic arithmetic and is struggling with some of the more tedious exercises in the book.
Homework Statement
I have a question
Relevant Equations
N/A
Here is my work** Can someone please tell me if this is correct?

mass = 27.8 g CaCI2
Number of CaCI2 in the compound = (unknown)
Number of CI- ions in the compound = (unknown)
Number of moles = mass/molar mass
To find the number of moles of CaCI2 first you find the molar mass of the compound.
1 mole Ca x 40.08 g Ca/1 mole Ca = 40.08 g
1 mole CI x 30.45 g CI/1 mole CI = 30.45 g
1 mole CI x 30.45 g CI/1 mole CI = 30.45 g
molar mass = (40.08 g + 35.45 g + 35.45 g) = 110.98 g/mol CaCI2
27.8 g CaCI2 x 1 mol CaCI2/110.98 g CaCI2 = 0.250 mol CaCI2
Now from equation No of Chloride ions are : 6.02 x 10^23 x 2 CI- ions =
1.204 x 10^23 CI- ions

dshoup
Homework Statement:: I have a question you mean: 'see below for the problem statement'
Homework Equations:: N/A Oh ?

Now from equation No of Chloride ions are : 6.02 x 10^23 x 2 CI- ions =
1.204 x 10^23 CI- ions
can you explain this ?

PS kudos for dealing with the dimensions properly in part a) !

Homework Statement:: I have a question
Homework Equations:: N/A

mass = 27.8 g CaCI2
Number of CaCI2 in the compound = (unknown)
Number of CI- ions in the compound = (unknown)
Please be more careful in writing the chemical symbols, particularly when you write I in place of l (lower-case letter ell).
##CI_2## would be a compound made up of a carbon (C) atom and two atoms of Iodine (I), which might or might not be an actual compound. Chlorine's symbol is Cl, not CI.

In addition there is a subscript entry in the ... drop down menu :

CaCl2 is so much easier on the eye

You have calculated the number of Cl- ions in a mole of CaCl2.
The job was to calculate the number in what is approximately ¼ mole of it.
Is it that difficult?

Is it difficult to see the answer is wrong?

It seems to me in several exercises you are making heavy weather of some rather tedious and pedantic exercises. All that is involved is some simple proportions. I suggest if necessary you revise on an elementary arithmetic book. (OK you need the concept of moles, Dalton's number, chemical compound.) But maybe you are making such a bad mistakes because it is very boring and mind-numbing. Maybe the way out is to tell yourself I want to learn about and understand some real chemistry. E.g. About these elements and compounds you are doing these calculations on. And read ahead in the textbook (hoping it is not all like this)!

BvU

## 1. How do I calculate the number of moles in CaCI2?

To calculate the number of moles in CaCI2, you will need to know the mass of the compound and its molar mass. Divide the mass of CaCI2 by its molar mass, which can be found by adding the atomic masses of calcium and chlorine. The result will be the number of moles of CaCI2.

## 2. What is the molar mass of CaCI2?

The molar mass of CaCI2 can be found by adding the atomic masses of calcium (40.08 g/mol) and chlorine (35.45 g/mol) together. This gives a molar mass of 75.53 g/mol.

## 3. How many ions are present in CaCI2?

There are three ions present in CaCI2: one calcium ion (Ca2+) and two chloride ions (2Cl-). This is because calcium has a charge of +2 and chlorine has a charge of -1.

## 4. How do I calculate the number of calcium ions in CaCI2?

To calculate the number of calcium ions in CaCI2, you will need to know the number of moles of CaCI2 and the ratio of calcium ions to moles of CaCI2. In this case, the ratio is 1:1, so the number of calcium ions will be the same as the number of moles of CaCI2.

## 5. How do I calculate the number of chloride ions in CaCI2?

Similar to calculating the number of calcium ions, to calculate the number of chloride ions in CaCI2, you will need to know the number of moles of CaCI2 and the ratio of chloride ions to moles of CaCI2. In this case, the ratio is 2:1, so the number of chloride ions will be twice the number of moles of CaCI2.

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