Calculating Max. Distance of Block on Turntable Rotating at 33 1/3 rev/min

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SUMMARY

The discussion centers on calculating the maximum distance a brass block can be placed from the axis of a turntable rotating at 33 1/3 revolutions per minute (rev/min) before sliding off. The coefficient of friction between the block and the turntable is given as µ = 0.17. The relevant equation derived is R ≤ µg / ω², where ω is the angular velocity in radians per second. This formula allows for determining the maximum radius (R) based on the frictional force and gravitational force acting on the block.

PREREQUISITES
  • Understanding of angular velocity and its conversion from revolutions per minute to radians per second.
  • Familiarity with the concepts of friction, specifically the coefficient of friction.
  • Basic knowledge of Newton's laws of motion, particularly the forces acting on an object in circular motion.
  • Ability to manipulate algebraic equations to solve for variables.
NEXT STEPS
  • Learn how to convert revolutions per minute to radians per second for angular velocity calculations.
  • Study the principles of circular motion and the forces involved, including centripetal force.
  • Explore the implications of different coefficients of friction on the stability of objects on rotating surfaces.
  • Investigate real-world applications of these principles in engineering and design of rotating machinery.
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JJ89
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The coefficient of friction between a certain brass block and a large revolving turntable is µ = 0.17. How far from the axis of rotation can the block be placed before it slides off the turntable if it is rotating at 33 1/3 rev/min?

i was wondering was this the equation to solve this question?
m ω^2 R <= µ m g

R <= µ g / ω^2



The Attempt at a Solution


 
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