Calculating Max Speed of 0.3 kg Mass on Horizontal Spring

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SUMMARY

The maximum speed of a 0.3 kg mass attached to a horizontal spring with a spring constant of 32 N/m can be calculated using the formula Vf = √(k/m * (xi² - xf²)). In this scenario, the mass is initially stretched 0.2 m from its relaxed position. The discussion highlights the need to determine the initial and final stretch of the spring to accurately compute the maximum speed, while also considering factors such as frictional force that may affect the outcome.

PREREQUISITES
  • Understanding of Hooke's Law and spring constants
  • Basic knowledge of kinetic and potential energy concepts
  • Familiarity with the formula for maximum speed in spring-mass systems
  • Ability to perform algebraic manipulations and solve equations
NEXT STEPS
  • Research the derivation of the maximum speed formula for spring-mass systems
  • Learn about the effects of friction on spring dynamics
  • Explore energy conservation principles in mechanical systems
  • Study the impact of varying spring constants on mass speed
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Students studying physics, particularly those focusing on mechanics and spring dynamics, as well as educators seeking to clarify concepts related to energy conservation and motion in spring systems.

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Homework Statement



If a mass of 0.3 kg is attached to a horizontal spring system with a spring constant of 32 N/m^2 is stretched 0.2 m from its relaxed length, what is the maximum speed the mass will attain when released from this position?



The Attempt at a Solution


i thought all you end up with is Vf=squareroot of k/m(xi^2-xf^2) but it is wrong.
 
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When the mass is at its maximum speed, what will be the stretch of the spring?
 
x_i=?\mbox{ and }x_f=?{ },{ }\mbox{how do you think?}
\mbox{does the statement is complete? frictional force?}
 
Last edited:

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