- #1
af86
- 10
- 0
Homework Statement
Calculate number of channels present in a lipid bilayer
q = 1.6^-19; D (diffusion constant) = 1.2E-9; C (Concentration); 4.36; k = 1.38E-23; T=298; d = 2.5E-9
Therefore G1 = 1.27E-17
Channel area = 7.07E-18
measured conductance (from injecting Na+ concentration of 100mM) = 149.24uS
Homework Equations
G1 (conductance) = q^2DC/kTd
Gm = g/[tex]\pi[/tex]r^2
The Attempt at a Solution
Conductance of a single channel = 1.27E-12 x 7.07E-18
Number of channels = Gm/G1 ??
Calculating the number of channels is what is getting to me. I have the area of the channel, and I have a measured conductance from injecting a concentration
Thanks!