Calculating Oxygen Gas Released from Heating Calcium Chlorate

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SUMMARY

The discussion focuses on calculating the volume of oxygen gas released from heating 5.00 grams of calcium chlorate (Ca(ClO3)2). The balanced chemical equation indicates that 1 mole of calcium chlorate produces 3 moles of oxygen gas (O2). Using the molar mass of calcium chlorate (207.7 g/mol) and the molar volume of oxygen (22.4 L/mol), the correct calculation yields approximately 1617 mL of O2, aligning with the expected answer of 1620 mL when rounded. The error in the initial calculation stemmed from incorrect mole ratio application.

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Homework Statement


How many millilitres of oxygen gas are released from heating 5.00 grams of calcium chlorate?

Homework Equations



Ca(ClO3)2→CaCl2+3O2

Ca(ClO3)2 =207.7g
CaCl2=110.98g
O2=22.4 g/L
Mole ratio= 3mol O2/1mol Ca(Clo3)2

The Attempt at a Solution


This is what I have but it is not coming out right and I just can't figure out where I am going wrong. I am having trouble with these kinds of problems.

(207.7 g/ 1 mol Ca(Clo3)2) X (1mol Ca(Clo3)2/3 mol O2) X (22.4 L O2/ 1 mol O2)= 1550.8
(this can't be right the answer is supposed to be 1620)
 
Last edited:
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Moles of Calcium Chlorate (Given Mass / Molar Mass)* Moles of dioxygen per mole of Calcium Chlorate (3) * Volume of 1 mole dioxygen (22.4 L / mol).

The answer is approximately 1617. (1620 if you approximately calculate it manually)
 
I now see where I went wrong! thank you :)
 

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