- #1

PsychonautQQ

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## Homework Statement

1.In the ``game'' of Russian roulette, the player inserts a single cartridge into the drum of a revolver, leaving the other five chambers of the drum empty. The player then spins the drum, aims at his/her head, and pulls the trigger. 1.What is the probability of the player still being alive after playing the game [tex]N[/tex] times?

2.What is the probability of the player surviving [tex]N-1[/tex] turns in this game, and then being shot the [tex]Nth[/tex] time he/she pulls the trigger?

3.What is the mean number of times the player gets to pull the trigger?

## The Attempt at a Solution

(I'm in the process of learning LaTex, but for now...)

1. The chances of the person still being with 5 chambers is

[tex]\sum_{n=zero}^4 \frac{1}{5-n}[/tex]

series from n=0 to n=4 (1/(5-n)

right? This would equate to 1/(5-0) + 1/(5-1) + 1/(5-2) etc etc...

i'm a bit stumped at question #2 however.

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