Calculating Tension, Work, and Power in Elevator Systems

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SUMMARY

The discussion focuses on calculating work and power in elevator systems, specifically analyzing a 1200-kg elevator lifted by a cable over 35 meters in 5.3 seconds. The work done by the tension in the cable is calculated using the formula W=FxD, resulting in 420,000 Joules. The work done by the elevator's weight is identified as negative due to the opposing direction of gravitational force, while the power provided by the tension is calculated as approximately 79,245.3 Watts using the formula P=W/T.

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1. a cable lifts a 1200-kg elevator at a constant velocity for a distance of 35 m in 5.3 seconds.

A.) What is the work done by the tension in the cable?
B.) What is the work done by the elevator's weight?
C.) What is the power provided by the tension in lifting the elevator?
 
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There are very simple equations one can use to solve these.
 
draw a free body diagram.. and write down the relevant equations u need
 
for A.) i did W=FxD so W=12000x35=420000
for B.) i wasn't sure how to do because isn't it the same thing as A?
and C.) P=W/T
P=420,000/5.3= 79245.3
not sure if they're right though..
 
A) that looks fine
B) no, the rope pulls up, what does the pull of gravity do to the elevator?
C) looks fine
 
when the rope pulls upwards and gravity pulls down, then gravity does negative work. Remember, gravity does negative work most of the time, since the rope is pulling up and gravity is pulling down, the direction of acceleration of gravity and acceleration of the elevator are not the same, therefore, negative work is being done by gravity. If the elevator was moving down then gravity would be doing positive work on the elevator.
 
a) correct
b)T=mg that means that w=mg and they are equal.
C)correct
 
This is a 2 and a half year old topic.:wink:
 

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