Because that's a definite-weight state of [tex]SU(3)[/tex] flavor. And by definite-weight state I mean an eigenstate of specific [tex]SU(3)[/tex] generators (specifically what are called Casimir operators, the analog of [tex]\vec{J}^2[/tex] for [tex]SU(2)[/tex]). It's analogous to working out the product states of two spin 1/2 particles, but a little bit more complicated because the algebra of [tex]SU(3)[/tex] has more generators than [tex]SU(2)[/tex].