Calculating the Fall Time of a High Diver from 36 m

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The discussion focuses on calculating the fall time of a high diver from a height of 36 meters, assuming a constant acceleration of 10 m/s². The relevant kinematic equation identified is x = (1/2)at², which relates distance, acceleration, and time. By applying this equation, the time interval for the diver's fall can be determined. The correct application of kinematic principles is essential for solving this problem accurately.

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If a high diver plunges from 36m above the water, what is the length of the time interval during which the diver falls through the air? - assume that throughout their dive, the diver is falling vertically from rest with an acceleration of 10\ ms^{-2}
I'm not sure how to answer this. I think I'm missing something really basic here.

Thanks for your help.
 
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Could you list the equation(s) you think are relevant to this problem? Hint: kinematic equations.
 
Oh. I've got it now. x=\frac{at^2}{2}. I missed that one when I looked through my formulas.

Thanks
 

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