Calculating the Mayan Date 0,2,3,5,10 Days Later from 8,10,193

[BurtZ]

Summary:: Given the Mayan date (8,10,193) determine the Mayan date that is 0,2,3,5,10 days later.

The Mayans used a complicated date system. The question asks: Given the Mayan date (8,10,193) determine the Mayan date that is 0,2,3,5,10 days later.

The system the Mayans used had two different calendars at the same time. They had a 260 day almanac with was made of two cycles - one of length thirteen and one of length 20. The second calendar had 365 days. This was divided into months of 20 days and an extra five period day. The triples were repeated after 18,980 days - 50 years. The first and second numbers in the triple connect to the 260 day almanac. The third is the day number in the 365 day year.
How can I find the date asked for in the question?

 

[jim mcnamara]

There is also the long count - the "8" in your example.

IMO, without at least a detailed guide of the system, date arithmetic (calendrics) is hard.
What resource do you have?
Have you tried: https://maya.nmai.si.edu/calendar/calendar-system
There are videos there on how each calendar works and how to use it -- each one of the three is considered as a calendar on its own.

Plus, I'm not sure how mathematical this question is, but let's leave it here in this forum.

 

[jim mcnamara]

Here is another detailed one, do not worry about the long count, examples of converting Gregorian dates.
https://stevemorse.org/jcal/mayanrules.htm

 

[BurtZ]

Here is another detailed one, do not worry about the long count, examples of converting Gregorian dates.
https://stevemorse.org/jcal/mayanrules.htm

Thanks! These resources look helpful.