- #1

scarecrow

- 139

- 0

I have a Gaussian trial wavefunction for the ground 1s state of H atom:

[tex]\psi (r)[/tex]= A Exp[-c r^2],

where

I'm trying to calculate the variational integral W(c) = < [tex]\psi (r)[/tex] |

My question is wouldn't the angular momentum term operator, [tex]L^2[/tex], in the Hamiltonian disappear since the trial wavefunction only depends on

(And by the way, how do I use all those mathematical typesettings on this board?)

[tex]\psi (r)[/tex]= A Exp[-c r^2],

where

*A*is the normalization constant and*c*is the variational parameter.I'm trying to calculate the variational integral W(c) = < [tex]\psi (r)[/tex] |

**H**| [tex]\psi (r)[/tex]>, where**H**is the Hamiltonian for the H-atom.My question is wouldn't the angular momentum term operator, [tex]L^2[/tex], in the Hamiltonian disappear since the trial wavefunction only depends on

*r*?(And by the way, how do I use all those mathematical typesettings on this board?)

Last edited: