MHB Calculating Work Done: Elevator Problem

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To calculate the work done in the elevator problem, the gravitational potential energy formula (mgh) is essential. For part (a), when the counterweight comes to rest at the original position of the cabin, the work done can be calculated based on the weight of the elevator and the height it was lifted. In part (b), if the counterweight is 20 feet below the original position, the work done will differ due to the change in height. The discussion emphasizes the importance of determining the appropriate coordinate axis for accurate calculations. Understanding these concepts is crucial for solving the problem effectively.
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An elevator cabin which weighs 3000 lb is lifted up 120 feet. It is connected with a counterweight of 3200 lb by a cable of length 200 feet weighing 4 lb per feet.

What work is done (or gained) if

a) the counterweight comes to rest at the same position as original position of the cabin,

b) 20 feet below the original position of the cabin.

Assume that the circumference of the turning wheel of the cable is 10 feet.
 
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I would use the work-energy theorem here. The change in energy will be the amount of work done. Can you compute $\Delta E$?
 
I don't know how to do this.Can you explain this for me?
 
First let me ask if this is for a physics course or for a calculus course...i.e., are you expected to do this dynamically or are you allowed to use energy considerations. Have you recently been studying gravitational potential energy?
 
It's calculus,yes we can use physics equations.And I do know some..But I don't know where to begin.
MarkFL said:
First let me ask if this is for a physics course or for a calculus course...i.e., are you expected to do this dynamically or are you allowed to use energy considerations. Have you recently been studying gravitational potential energy?
 
Okay, do you know how to determine the gravitational potential energy of an object?
 
MarkFL said:
Okay, do you know how to determine the gravitational potential energy of an object?

mgh?
 
Yes, good! :D

So where do you think would be an appropriate place to orient the origin of our coordinate axis?
 

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