Calculating Young's Modulus with Force and Extension Measurements

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Homework Help Overview

The discussion revolves around calculating Young's Modulus using provided force and extension measurements. Participants are exploring the relationship between stress and strain in the context of material properties.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the formulas for stress and strain, and how they relate to Young's Modulus. There are questions about which data points to use from the provided measurements and whether a graph is necessary for analysis. Clarifications are sought regarding the dimensions of the area mentioned in the data.

Discussion Status

The conversation includes attempts to clarify the formulas involved and the application of the data. Some participants are considering different approaches, such as plotting a graph, while others are focused on direct calculations. There is no explicit consensus on the method to be used.

Contextual Notes

Participants are working with specific measurements and formulas, but there are uncertainties regarding the interpretation of the area dimensions and the selection of data points for calculations.

ACCC12
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hi

i have been given these results in order to work out the young's modulus can any 1 tell me how i go about doing this

Force (kN) Extension (mm)
0.5 0.003
1 0.011
1.5 0.019
2 0.021
2.5 0.024
3 0.032
3.5 0.040
4 0.043
4.5 0.050
5 0.060
5.5 0.064
6 0.070
6.5 0.076
7 0.081

Area 50mm by 5

thanks for all your help
 
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E=\frac{stress}{strain}


Write the formula for stress and the formula fopr strain and then simply the formula for Young's Modulus,E.
 
i know the equation but i didnt know which part of the data to use, do i just take any part of the data from the table or do i have to plot a graph! thanks for all you help!
 
ACCC12 said:
i know the equation but i didnt know which part of the data to use, do i just take any part of the data from the table or do i have to plot a graph! thanks for all you help!

what is meant by "area 50mm by 5 " in your data ? please explain.
 
E=\frac{\frac{F}{A}}{\frac{e}{l}}


E=\frac{Fl}{Ae}

Right?


From your graph, what does the fraction F/e represent?
 
50mm length, 5mm diameter
 
got the answer to be 5.3 is that correct!

equation used

2.5 x 50
----------
981.75 x 0.024
 
any takers! thanks
 

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