Calculation of PH,(using Henderson Hasselbalch equation)

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SUMMARY

The discussion focuses on calculating the pH of various solutions using the Henderson-Hasselbalch equation, specifically for acetic acid (CH3COOH) and sodium acetate (CH3COONa). The pH values for five tubes were calculated, with tube 1 yielding a pH of 3.9, while precipitation is expected to occur in tube 2. The pKa of acetic acid is confirmed at 4.7, and logarithmic values for concentrations were provided to facilitate calculations.

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  • Understanding of the Henderson-Hasselbalch equation
  • Knowledge of pKa values, specifically for acetic acid (pKa = 4.7)
  • Basic logarithmic calculations
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1. Homework Statement
Calculate each tube's PH using the equation.In which tube precipitation will take place?why?
Ingredients TUBE 1 2 3 4 5
0.5 M CH3COOH(ml) 3.4 2.8 2.0 1.2 0.6
0.5 M CH3COONa(ml) 0.6 1.2 2.0 2.8 3.4
casein solution 0.5%(ml) 1 1 1 1 1


given; log 0.6=-0.2218 log2=0.3010 log 3.4=0.5315 log 1.2=0.0792 log2.8=0.4472
pk CH3COOH=4.7

Homework Equations


Ph=pk+log (A/HA)





The Attempt at a Solution

Not sure if any of these are correct
Concentration:
tube 1;(0.5)(3.4) + (O.5)(O.6)=1.7 + 0.3 ph =4.7+log (0,3/1,7)=3,9
precipitation takes place in tube 2
Thank you
 
Last edited:
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What you wrote is hard to follow, but at least I think I can confirm pH in the first tube looks OK.
 

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