Can anyone tell me what is tan 50 in fractions?

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SUMMARY

The discussion focuses on calculating the tangent of 50 degrees using trigonometric identities. The key steps involve expressing cos(20) through the equation 4y³ - 3y = 1/2, derived from the cosine of 60 degrees. The half-angle formula is applied to find cos(10), and the summation formula for cosine is used to relate cos(50) to cos(60) and sin(60). The final expression for tan(50) is obtained by utilizing the identity sin(50) = √(1 - cos²(50)).

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benzun_1999
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Hi
can anyone tell me what is tan 50 in fractions?
-benzun
 
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What's 50?
Radians or degrees?
 
I'll assume that "50" is in degrees:
What you need is basically an expression for \cos(20) , all the rest follow from this:

1. \cos(60)=\cos(3*20)=4\cos^{3}20-3\cos(20)
by simple trigonometric identities.
Hence, setting y=\cos(20) you find the required value by solving for y in the equation:
4y^{3}-3y=\frac{1}{2} since \cos(60)=\frac{1}{2}
You need therefore the formula for roots of 3.degree polynomials.

2. \cos(10)=\frac{1+y}{2} by the half-angle formula.

3. \cos(50)=\cos(60)\cos(10)+\sin(60)\sqrt{1-\cos^{2}(10)}
by the summation formula for cosine.

4. By noting \sin(50)=\sqrt{1-\cos^{2}(50)} you may find your expression for tan(50)
 
sorry,
i ment degrees only
Thanks
Is it possible to construct 50 degrees with a compas and scale only?
-benzun
 
benzun_1999 said:
Is it possible to construct 50 degrees with a compas and scale only?
-benzun

See
http://planetmath.org/encyclopedia/ConstructibleAnglesWithIntegerValuesInDegrees.html
 
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