Can Column Vectors be Multiplied?

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Discussion Overview

The discussion revolves around the multiplication of column vectors, specifically examining the relationship between the inner product and outer product of a column vector and its conjugate transpose. The scope includes theoretical aspects of linear algebra and vector operations.

Discussion Character

  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant questions whether the equality \(\mathbf{h}^*\mathbf{h}=\mathbf{h}\mathbf{h}^*\) holds for an \(N \times 1\) column vector \(\mathbf{h}\).
  • Another participant suggests testing the equality with a specific example, \(\mathbf{h} = [1, 0]^*\), and mentions the concepts of inner product and outer product as relevant operations.
  • It is noted that \(\mathbf{h}\mathbf{h}^*\) represents the outer product and \(\mathbf{h}^*\mathbf{h}\) represents the inner product, with a clarification that the inner product is typically a real number rather than a \(1 \times 1\) matrix.
  • Further discussion highlights the applications of the outer product in dual vector spaces and its relevance in quantum mechanics (QM) and general relativity (GR).

Areas of Agreement / Disagreement

Participants generally agree on the definitions and applications of inner and outer products, but the initial question regarding the equality of the two expressions remains unresolved.

Contextual Notes

The discussion does not resolve whether the equality holds under all conditions, and there may be assumptions regarding the properties of the vectors involved that are not explicitly stated.

EngWiPy
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Hello,

Suppose that [tex]\mathbf{h}[/tex] is an [tex]N\times 1[/tex] column vector. Can we say that:

[tex]\mathbf{h}^*\mathbf{h}=\mathbf{h}\mathbf{h}^*[/tex]

where * means complex conjugate transpose?

Thanks in advance
 
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Try it out for yourself. Take [tex]\mathbf{h} = [1, 0]^*[/tex].

Furthermore, if you're not familiar with them, you may want to look up the terms inner product and outer product. They are operations on vectors that, conveniently, map to matrix multiplication between conjugate transposes.
 
Tac-Tics said:
Try it out for yourself. Take [tex]\mathbf{h} = [1, 0]^*[/tex].

Furthermore, if you're not familiar with them, you may want to look up the terms inner product and outer product. They are operations on vectors that, conveniently, map to matrix multiplication between conjugate transposes.

Ok then, [tex]\mathbf{h}\mathbf{h}^*[/tex] is the outer product of the two vectors, and [tex]\mathbf{h}^*\mathbf{h}[/tex] is the inner product of them. Right?
 
S_David said:
Ok then, [tex]\mathbf{h}\mathbf{h}^*[/tex] is the outer product of the two vectors, and [tex]\mathbf{h}^*\mathbf{h}[/tex] is the inner product of them. Right?

Yup!

Usually, the inner product is taken to be a real number, not a 1x1 matrix. But the two ideas are identical. The inner product is well known for it's use is defining orthogonality and angles.

The outer product is less commonly known. It has applications when working with dual vector spaces. It's useful in QM and GR.
 
Tac-Tics said:
Yup!

Usually, the inner product is taken to be a real number, not a 1x1 matrix. But the two ideas are identical. The inner product is well known for it's use is defining orthogonality and angles.

The outer product is less commonly known. It has applications when working with dual vector spaces. It's useful in QM and GR.

Ok thank you Tac-Tics.

Best regards
 

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