Can exact Lorentzian kinematics emerge from Euclidean space?

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TL;DR
Can a theory on 4D Euclidean space produce exact Lorentz transformations and an invariant signal speed while the underlying metric stays Euclidean and no Wick rotation is used?
Can exact Lorentzian kinematics arise from a theory formulated on a four-dimensional Euclidean space without a Wick rotation?

Suppose a theory is formulated on a four-dimensional Euclidean space with a positive-definite metric.

Assume that:

  • the metric always remains Euclidean;
  • no coordinate is analytically continued (t \to it);
  • no real coordinate transformation is claimed to convert the Euclidean metric into a Minkowski metric.
Can such a theory nevertheless contain a physical sector in which the Lorentz transformations hold exactly, with an exact finite invariant signal speed?

I do not mean approximate Lorentz invariance in a low-energy or long-wavelength limit. I mean exact special-relativistic kinematics.

The usual signature argument shows that a positive-definite Euclidean metric cannot be transformed into a Lorentzian metric by a real nonsingular coordinate transformation.

But does it also imply the stronger statement that exact Lorentzian kinematics cannot arise in a theory whose underlying geometric structure remains Euclidean?

In other words, are these two statements equivalent?

  1. A Euclidean metric cannot be transformed into a Lorentzian metric.
  2. A theory formulated on Euclidean space cannot produce exact Lorentz transformations in its physical sector.
The first statement is standard. Does the second actually follow from it?
 
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Ans said:
Suppose a theory is formulated on a four-dimensional Euclidean space with a positive-definite metric.

Assume that:

  • the metric always remains Euclidean;
  • no coordinate is analytically continued (t \to it);
  • no real coordinate transformation is claimed to convert the Euclidean metric into a Minkowski metric.
Can such a theory nevertheless contain a physical sector in which the Lorentz transformations hold exactly, with an exact finite invariant signal speed?
Given the assumptions in the paper "Nothing but Relativity", including group properties of a transformation (two boosts in one direction are equivalent to one boost of the same form),
https://arxiv.org/abs/physics/0302045
the Lorentz transformation as physically relevant follows only for one of three cases.

Transformartion equation (27) in the article can be derived without the 2nd postulate.
K<0 : can be excluded (causality would be not invariant)
K=0 : makes it the Galilean transformation
K>0 : makes it the Lorentz transformation
An experiment is needed to decide between Galilean- or Lorentz-transformation.

From this with twin paradox-experiments we know, that the Lorentz transformation is physically valid.

With unit system ##c=1##, in the ##xt##-plane:
LT
##(1)\ x'=\gamma (x-vt)##
##(2)\ t'=\gamma (t-vx)##
Add (1) and (2):
##(3)\ x'+t'=\gamma (x+t-v(x+t))=\gamma(1-v)(x+t)##
Subtract (2) from (1):
##(4)\ x'-t'=\gamma (x-t+v(x-t))=\gamma(1+v)(x-t)##
Multiply (3) and (4):
##(5)\ x'^2-t'^2=\gamma^2(1-v^2)(x^2-t^2)##
$$x'^2-t'^2=x^2-t^2$$
The Lorentz transformation is equivalent to Minkowski metric and not to 4D-Euclidean metric.
 
Ans said:
Can such a theory nevertheless contain a physical sector in which the Lorentz transformations hold exactly, with an exact finite invariant signal speed?
The concept of "signal speed" would not even make sense in a Euclidean theory such as you describe, since such a theory has no notion of "time". In standard GR terminology, all four coordinates on the 4D Euclidean space are spacelike.
 
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PeterDonis said:
A Galilean spacetime is not the same thing as a 4D Euclidean space.
That's true, but I didn't claim that it is the same. With "4D-Euclidean metric" I referred only to the OP.
 
I think it depends what you mean. You can have Lorentzian dynamics in Lorentz Ether Theory, which has a 3d Euclidean space and a separate time parameter, and the Lorentz behaviour that provides the illusion of a 4d spacetime happens for some unspecified reason.

If you mean a 4d Euclidean space where one direction is timelike, I don't see what would pick out the dimension to call timelike. You can certainly draw such things (it's what a Minkowski diagram is), but there we impose a Minkowski metric on the diagram artificially and just arbitrarily pick a couple of directions to call null.

So my immediate thought is that you can impose Lorentzian dynamics on other geometries, but it has to be put in manually.
 
Only if you solve the problem of time, as PeterDonis pointed out, in R4 you have four spatial directions and no time.

Some related work: analogue gravity (Barceló, Liberati & Visser, Analogue Gravity, Living Rev. Relativity 14, 3, 2011), effective Lorentzian metrics emerging from non-relativistic substrates. It's close to the spirit of the question, though not a full answer: it gives effective/emergent Lorentz invariance, not the exact kinematics the OP is asking about.
 
Last edited:
PeterDonis said:
A Galilean spacetime is not the same thing as a 4D Euclidean space.
Yes. It is the unphysical first case ##K=-1## in posting #2, which is an Euclidean rotation in the ##xt## plane.
##\begin{pmatrix}
x'\\
t'
\end{pmatrix}
=
\frac{1}{\sqrt{1-Kv^2}}
\begin{pmatrix}
1 & -v\\
-Kv & 1
\end{pmatrix}##

##\begin{pmatrix}
x'\\
t'
\end{pmatrix}
=
\frac{1}{\sqrt{1+v^2}}
\begin{pmatrix}
1 & -v\\
v & 1
\end{pmatrix}
\begin{pmatrix}
x\\
t
\end{pmatrix}##


##\begin{pmatrix}
x'\\
t'
\end{pmatrix}
=
\begin{pmatrix}
\cos\theta & -\sin\theta\\
\sin\theta & \cos\theta
\end{pmatrix}
\begin{pmatrix}
x\\
t
\end{pmatrix},
\qquad
\theta=\arctan v##
 
Sagittarius A-Star said:
It is the unphysical first case ##K=-1## in posting #2, which is an Euclidean rotation in the ##xt## plane.
In this case ##t## isn't timelike, so there's no justification for even calling it a "time". But I guess one could view that as yet another reason for calling it "unphysical".
 
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Ibix said:
a 4d Euclidean space where one direction is timelike
There is no such thing. "Timelike" means a squared interval of the opposite sign from spacelike. There is no such thing in a Euclidean space; all squared intervals have the same sign.
 
Ans said:
signal speed
I also don’t know what speed would mean in such a manifold.

The Lorentz transform treats time and space differently. Since in your space there is nothing that distinguishes the different directions any method that ends in the Lorentz transform would not be natural.
 
PeterDonis said:
There is no such thing. "Timelike" means a squared interval of the opposite sign from spacelike. There is no such thing in a Euclidean space; all squared intervals have the same sign.
That's kind of the point I was trying to make - all the directions are the same, so which one is time?

The only solution I can think of is something like a Minkowski diagram, which is a Euclidean plane where we impose Lorentzian physics by fiat rather than having it follow from the geometry.
 
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Ibix said:
all the directions are the same, so which one is time?
None of them.

Ibix said:
The only solution I can think of is something like a Minkowski diagram, which is a Euclidean plane where we impose Lorentzian physics by fiat rather than having it follow from the geometry.
You can't "impose Lorentzian physics by fiat" in a geometry that has all spacelike intervals. The whole point of Lorentzian physics is that the geometry is Minkowski, not Euclidean. The OP even rules out the dodge of using Wick rotation to construct a kinda sorta correspondence between the two.
 
PeterDonis said:
You can't "impose Lorentzian physics by fiat" in a geometry that has all spacelike intervals.
I could observe the paths of some particles constrained (for the sake of simplicity) to move in 1d. Then I could plot them on a Minkowski diagram. Then I could cut off the top half of the diagram and pass it to you, and you could then fill in the top half using your knowledge of relativity and (give or take measurement precision etc) it would exactly reproduce the top half of my diagram. That is, the top half of the diagram is predictable from the bottom half given knowledge of relativistic physics. What is that if not relativistic physics imposed on a Euclidean plane?
 
Ibix said:
the top half of the diagram is predictable from the bottom half given knowledge of relativistic physics. What is that if not relativistic physics imposed on a Euclidean plane?
The fact that I can draw the diagram of relativistic physics on a Euclidean plane does not mean I am imposing relativistic physics on a Euclidean plane. The diagram is just a diagram of the physics; it's not the actual physics. The map is not the territory.
 
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Sagittarius A-Star said:
Given the assumptions in the paper "Nothing but Relativity", including group properties of a transformation (two boosts in one direction are equivalent to one boost of the same form),
https://arxiv.org/abs/physics/0302045
the Lorentz transformation as physically relevant follows only for one of three cases.
....
The Lorentz transformation is equivalent to Minkowski metric and not to 4D-Euclidean metric.
I think your derivation is fine once (x) and (t) are already taken to be physical space and time coordinates. Then we already have inertial frames, relative velocity, etc., and the Galilean/Lorentz alternatives follow in the usual way.

But I think this may actually be the key point of my question.

PeterDonis, Dale and Ibix are right that in a genuinely Euclidean four-dimensional space none of the four directions is timelike. I agree. Simply choosing one Euclidean coordinate and calling it time would not solve anything.

So maybe the question is whether we have to identify the underlying four-dimensional geometry with physical spacetime in the first place.

Could the underlying geometry have four equivalent Euclidean directions, none of which is physical time, while physical time and the event structure arise at another level? And could the resulting structure then obey the Lorentz transformations exactly?

This is also why Roberto Pavani's comment about the problem of time seems relevant. If time has to be fundamental, I don't see how the construction could work. If time itself can emerge, the situation seems less obvious.

What I am trying to understand is whether there is a theorem that rules out this second possibility. The signature argument tells us that a Euclidean metric cannot be transformed into a Minkowski metric. But does it also tell us that a different physical spacetime structure cannot arise on top of an underlying Euclidean one?
 
I think the two spaces have to be kept separate, like Fourier space vs the function space the transform acts on.
Then you can set up a relation pairing each ## (x,E_i ) ## in ## \mathbb{R}^4 ## with a ## ( y, M_i ) ## in ## \mathbb{R}^{3,1} ##.
However, the Lorentzian structure would still live only in ## \mathbb{R}^{3,1} ##.

Note that in this view, on the ## \mathbb{R}^4 ## side there will be no scale, because the two spaces are separate. The scale belongs to ## \mathbb{R}^{3,1} ##.

About the theorem, I doubt one can exist, simply because there are infinitely many possible mappings between the two spaces.
 
Sagittarius A-Star said:
I don't know, but I found something related:
https://mathworld.wolfram.com/EuclideanQuantumFieldTheory.html
This involves analytic continuation of the time coordinate, which the OP rules out, so it's not what's being asked about in this thread.

Note that analytic continuation means the Euclidean region is not an "overlay" on the Minkowski region; it's a different region, just as the imaginary axis in the complex plane is a different region from the real axis.
 
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I looked into this a bit more. Apparently there have been several attempts to formulate SR using 4D Euclidean geometry.

For example, Alexander Gersten published Euclidean Special Relativity in Foundations of Physics, and J. M. C. Montanus published a proper-time formulation there as well.

But after looking at these papers, I am not sure they solve the problem we are discussing. Gersten starts from the usual Minkowski interval and then introduces Euclidean coordinates. In the proper-time approach, proper time is already used as the fourth Euclidean coordinate.

So in both cases a substantial part of the relativistic structure seems to be there from the beginning. This looks close to Ibix's point that one can put Lorentzian physics on top of another geometry, but then it has basically been put in by hand.

What I am wondering is whether the harder version is possible: can exact SR arise naturally from a genuinely Euclidean starting point, rather than being encoded into it?

Maybe the signature itself is not the main problem. Perhaps the real question is whether time and the physical event structure have to be fundamental in the first place.
 
Ans said:
can exact SR arise naturally from a genuinely Euclidean starting point, rather than being encoded into it?
Isn't that what we already answered?

I have never seen such a thing, and I don't think it would be possible. Particularly not the "naturally" qualification. There is no natural way to single out one dimension.
 
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Ans said:
In the proper-time approach, proper time is already used as the fourth Euclidean coordinate.
Proper time can't be a coordinate, because different observers that follow different worldlines between the same two events can have different proper times (as in the "twin paradox"). A coordinate has to give a unique number to each event.

Ans said:
one can put Lorentzian physics on top of another geometry
No, one can't. As I responded to Ibix, the whole point of Lorentzian physics is that the spacetime geometry is Minkowski. You can't "overlay" one geometry on another. You can make a map of geometry B on a surface with geometry A, but saying that that means the actual physics involves geometry A is like saying, to borrow from an old Beyond the Fringe sketch, that coloring Venezuela blue on a map in your atlas is the same thing as the actual country of Venezuela being blue, with the colors we actually see being an "overlay" on the blue.

Ans said:
Maybe the signature itself is not the main problem.
It certainly is, since the signature is what distinguishes Minkowski from Euclidean geometry.

Ans said:
Perhaps the real question is whether time and the physical event structure have to be fundamental in the first place.
There is research being done along these lines--for example, loop quantum gravity--but they are not trying to construct Lorentzian physics on top of some other geometry, Euclidean or otherwise. They are trying to construct Lorentzian physics as being emergent from something that isn't geometry at all.
 
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PeterDonis said:
Proper time can't be a coordinate, because different observers that follow different worldlines between the same two events can have different proper times (as in the "twin paradox"). A coordinate has to give a unique number to each event.
Strongly agree
 
Ibix said:
The only solution I can think of is something like a Minkowski diagram, which is a Euclidean plane where we impose Lorentzian physics by fiat rather than having it follow from the geometry.

I would say that a Minkowski diagram is drawn--not on a Euclidean plane--but on an affine plane (where there is a sense of parallelism, but no notion to compare the sizes of vectors in different directions [and thus no "dot-product"]).
 
After moderator review, the thread will remain closed as the OP question has been addressed.

@Ans if you have a reference to an actual published paper (meaning a link to where it is posted online, which journal, etc.--arxiv.org preprint pages will have this information if a paper has been published) that claims that what you are asking about is possible, you can provide it to me by PM and the moderators will review it to see if it merits further discussion.