Can Hopf's Maximum Principle imply f(r) = 0 for X(r) with compact support?

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SUMMARY

Hopf's maximum principle cannot be used to conclude that f(r) = 0 for the function X(r) with compact support. The discussion highlights that if X(r) approaches zero as r approaches infinity and is defined as X(r) = -(\partial f / \partial r)^2, it does not imply that f(r) must be zero everywhere. A counterexample provided is X(r) = -1/r^2, which leads to f(r) = log(r), demonstrating that f(r) can be non-zero despite the conditions on X(r).

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haushofer
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Hi,

it's been a while since I've explicitly dealt with differential equations. I have a question concerning "Hopf's maximum principle". The situation is as follows.

Let's say I have a function X(r) for which I have

[tex] \lim_{r \rightarrow\infty}X(r) = 0[/tex]

This function X(r) satisfies the following condition for some arbitrary function f(r):

[tex] X(r) = - \Bigl(\frac{\partial f}{\partial r}\Bigr)^2[/tex]

Can I now use Hopf's maximum principle and state that

[tex] f(r) = 0[/tex]

everywhere? Do things change when I consider X(r) to have compact support? Maybe there is an easy counterexample if this conclusion is false, but any input would be welcome! :)
 
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Mmmm, if I pick [tex]X = \frac{-1}{r^2} [/itex] I get [tex]f(r) =\log{r}[/itex] which is certainly not zero everywhere.[/tex][/tex]
 

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