Can k be equal to 4 in the equation k + 2 = 3^(n)?

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SUMMARY

The equation k + 2 = 3^(n) indicates that k must be an integer such that k + 2 results in a power of 3, where n is a positive integer. The discussion concludes that k cannot equal 4, as this results in k + 2 equaling 6, which is not a power of 3. Therefore, the only value of k that cannot satisfy the equation is 4.

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If n is a positive integer and k + 2 = 3^(n), which of the following could NOT be a value of k?

A. 1
B. 4
C. 7
D. 25
E. 79

I say the answer is B or 4.

When k = 4, k + 2 becomes 6.
However, there is no power we can raised 3 to that will yield 6.

Is my reasoning correct?
 
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RTCNTC said:
If n is a positive integer and k + 2 = 3^(n), which of the following could NOT be a value of k?

A. 1
B. 4
C. 7
D. 25
E. 79

I say the answer is B or 4.

When k = 4, k + 2 becomes 6.
However, there is no power we can raised 3 to that will yield 6.

Is my reasoning correct?
Looks good to me!

-Dan
 
Or since 3^(n) is odd, then k can't be 4.
 

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