Can Mesh Analysis with Three Loops Solve a Four-Loop Circuit?

AI Thread Summary
The discussion revolves around solving a four-loop circuit using mesh analysis with only three loops, as suggested by previous guidance. The user struggles with obtaining correct results in their Excel spreadsheet despite following the loop equations. Key advice includes ensuring the accuracy of voltage signs in the equations and using a small value (0.0001) in the matrix to facilitate calculations. The user ultimately finds success by adjusting the spreadsheet input, confirming that the loop equations were correct. The conversation highlights the importance of careful setup in computational tools for circuit analysis.
billyray
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Homework Statement


I have a circuit that I am to analyse and find I. I am told to use an excel matrix sheet given to me to solve 3 unknowns. I have 4 loops so this is a problem. I have made an attempt using three loops and referred to a previous thread on here for some help. It says I can do it with three loops.
https://www.physicsforums.com/threads/ac-circuit-analysis-mesh-and-nodal.791744/
[/B]

Homework Equations

I have attempted the question many times and am including my results. They do not seem to agree with the results for the agreed answer on here.
Loop 1 --- 120-(2)I1-(I1-I2)(-j5)=0
Loop2 --- (-j5)(I2-I1)+(j4)(I2-I3)-14.14+j14.14=0
Loop3 --- (j4)(I3-I2)+(4)I3-j120=0

Answers;
I1=19.1624+j12.5642
I2= 14.1367-j3.77088
I3= 23.9538+j20.1829 [/B]
I can't seem to upload spread sheet

The Attempt at a Solution


I am incuding this and a spead sheet I am using. any pointers would be amazing as I am completely lost wheln I use the spreadsheet.[/B]
 

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here is the pic of the spread sheet
 

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billyray said:
Loop 1 --- 120-(2)I1-(I1-I2)(-j5)=0
Loop2 --- (-j5)(I2-I1)+(j4)(I2-I3)-14.14+j14.14=0
Loop3 --- (j4)(I3-I2)+(4)I3-j120=0
Are you confident about the sign of the voltage terms in loops 2 and 3? Read through the related conversation with the OP in the thread you referenced: he had the same issue!
 
Last edited:
hi gneil

thanks again for help. I have changed my answers but they still won't work in spread sheet
 

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billyray said:
hi gneil

thanks again for help. I have changed my answers but they still won't work in spread sheet
As far as I can tell with a quick glance, your recent attemp2.pdf shows correct loop equations. Good!

Regarding the spreadsheet's inability to solve the equations, take a look at the conversation that occurred in the thread that you referenced previously, starting around post #98 :wink:
 
thanks gneill will do tommorow. Thanks again so much
 
I'm trying to follow along. I put a 0.001 in the center cell of the Real matrix, as the warning suggested. This allows the spreadsheet to calculate values.
I put the same matrix into Matlab and solved the system and arrive at the same answers as the spreadsheet.
As far as I can tell, your loops and matrices look correct. Are the answers in the original post the "correct" answers that you are supposed to arrive at?
 
I have done this question and can tell you that I couldn't get the thing to work at all with some zero values. As scottdave above says, you need to put in a very small number just to allow it to compute.

Having just looked at my tutor feedback document, I did get the phases incorrect in my answer (+ instead of -), but the magnitudes were all correct, and mine don't match any of those in your original post.
 
Matlab is commercial software package. If you don't have access to that, Scilab and Octave are pretty good alternatives, which are free.
 
  • #10
Thanks scottdave and Numbskull.

I have obtained the correct answers by entering 0.0001 in the spreadsheet. Thanks for help though. I always thought it would be me wrong and not the spreadsheet
 

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