Can partial vanishing of Poisson bracket determine local constants of motion?

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SUMMARY

The discussion centers on the implications of the Poisson bracket between a Hamiltonian and a function f defined on the entire phase space. It establishes that if the Poisson bracket {f, H} vanishes on a subset of the phase space, f remains a constant of motion along trajectories within that subset. However, the participants note that local constants of motion derived from this condition may lack significant physical relevance when considering analytic continuation.

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  • Understanding of Hamiltonian mechanics
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  • Knowledge of phase space concepts
  • Basic principles of analytic continuation
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This discussion is beneficial for theoretical physicists, mathematicians specializing in dynamical systems, and students studying Hamiltonian mechanics who seek to deepen their understanding of constants of motion and their physical implications.

giova7_89
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I don't know if this is the right place to post this, but my question is: if i have an Hamiltonian defined on the whole phase space and a function f which is also defined on the whole phase space and doesn't depend explicitly on time, i know that if its poisson bracket with the Hamiltonian vanishes everywhere, f is a constant of the motion. But what happens if this poisson bracket doesn't vanish everywhere, but only on a subset of the phase space? This subset could be for example the one i get from the equation {f,H}=0

Thanks!
 
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Welcome giova7_89,
If the locus of {f,H}=0 contains a trajectory, f will indeed be constant for that trajectory. If one considers the analytic continuation, one must say that such local constants have little physical significance.
 

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