Can the Harmonic Sum be Proven Using a Newer Method?

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    Harmonic Sum
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Discussion Overview

The discussion centers around the harmonic sum and its relation to the series involving the squared harmonic numbers, specifically the expression $$\sum_{k\geq 1} \frac{H^2_k}{k^2}$$ and its evaluation in terms of $\zeta(4)$. Participants explore the possibility of proving this sum using newer methods, referencing a paper by D. Borwein and J. M. Borwein from 1995.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • Several participants reiterate the sum $$\sum_{k\geq 1} \frac{H^2_k}{k^2}=\frac{17}{4}\zeta(4)=\frac{17\pi^4}{360}$$ as a focal point for discussion.
  • One participant mentions reading the original paper and considers the problem a good exercise, indicating a desire to find their own solution.
  • Another participant expresses difficulty with the paper, particularly with the corollary work, and hopes for a simpler, newer perspective on the problem.
  • There is a note about expectations in the Challenge Questions and Puzzles sub-forum regarding having a solution ready when posting a problem.
  • One participant acknowledges knowing the solution is in the paper but describes it as lengthy and complex, expressing a hope for a more straightforward method.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the method of proof or the expectations for posting solutions. There are multiple viewpoints regarding the complexity of the existing solution and the desire for newer methods.

Contextual Notes

Some participants express uncertainty about the expectations for posting solutions in the forum, and there is a lack of clarity on whether the original paper's method is the only approach available.

alyafey22
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Prove the following

$$\sum_{k\geq 1} \frac{H^2_k}{k^2}=\frac{17}{4}\zeta(4)=\frac{17\pi^4}{360}$$

$$\mbox{where }\,\,H^2_k =\left( 1+\frac{1}{2}+\frac{1}{3}+\cdots \frac{1}{k}\right)^2$$​
 
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Actually , I haven't even tried it . I was reading the paper and thought it is a good exercise. I will look for a solution of my own .
 
ZaidAlyafey said:
Actually , I haven't even tried it . I was reading the paper and thought it is a good exercise. I will look for a solution of my own .
Ouch! I thought that paper was pretty brutal. I could follow the work on the integral but got lost on the Corollary work. I was kind of hoping you had a newer (and simpler) view on the matter.

-Dan
 
ZaidAlyafey said:
Actually , I haven't even tried it . I was reading the paper and thought it is a good exercise. I will look for a solution of my own .

Zaid,

When a problem is posted here in the Challenge Questions and Puzzles sub-forum, it is expected that you already have a solution ready to post after giving our members a fair amount of time to solve it, as per http://www.mathhelpboards.com/f28/guidelines-posting-answering-challenging-problem-puzzle-3875/.
 
MarkFL said:
Zaid,

When a problem is posted here in the Challenge Questions and Puzzles sub-forum, it is expected that you already have a solution ready to post after giving our members a fair amount of time to solve it, as per http://www.mathhelpboards.com/f28/guidelines-posting-answering-challenging-problem-puzzle-3875/.

I know the solution , it is in the paper . But it is very long and requires lots of things to work out . I was hoping for someone to post a newer method .

If that doesn't suit here , you can move the topic to an appropriate section .
 
ZaidAlyafey said:
I know the solution , it is in the paper . But it is very long and requires lots of things to work out . I was hoping for someone to post a newer method .

If that doesn't suit here , you can move the topic to an appropriate section .

No need, I interpreted your statement "I haven't even tried it" as meaning you had not attempted the problem. :D
 

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