Can the lorentz group be covered by single-parameter subgroups?

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SUMMARY

The Lorentz group consists of four disconnected components, with the component connected to the identity being expressible through single-parameter subgroups. Specifically, any element in this connected component can be represented as e^{i theta^a T^A}, where theta^a are parameters and T^A are generators of the Lorentz algebra. This representation is a fundamental aspect of relativistic quantum mechanics, as confirmed by various textbooks in the field. The Lorentz algebra is six-dimensional, which underlines the complexity of its structure.

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  • Understanding of the Lorentz group and its components
  • Familiarity with the concept of single-parameter subgroups
  • Knowledge of the Lorentz algebra and its dimensionality
  • Basic principles of relativistic quantum mechanics
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wdlang
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we all know the lorentz group is of four disconnected components

about the component connected to the unit element,

is it coverable with single-parameter subgroups?

put it in another way

are all the elements in this component of the form exp(A)?

i am studying relativistic quantum mechanics, and i find that most textbooks take this to be guaranteed.
 
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No; the Lorentz algebra is six-dimensional. Yes, you can write any element in the connected-to-the-identity part of the Lorentz group in the form e^{i theta^a T^A}.
 

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