Can the Other Eigenvalue Be Measured After an Initial Measurement?

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SUMMARY

The discussion centers on the measurement of eigenvalues in quantum mechanics, specifically whether the second eigenvalue, a2, can be measured after an initial measurement yielding eigenvalue a1. It is established that if the operator corresponding to the eigenstates |ν1⟩ and |ν2⟩ commutes with the Hamiltonian, measuring a2 post a1 is not possible. Conversely, if the operator does not commute with the Hamiltonian, measuring a2 is feasible. The time evolution of the state is described using the time evolution operator e^{-i\hat{H}t/\hbar}, which transforms the state |ν1⟩ into a superposition of |ν1⟩ and |ν2⟩.

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mangokiller
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A ket is expanded as \vert \nu \rangle = c_1\vert \nu_1\rangle+c_2\vert \nu_{2}\rangle.

A measurement results in the eigenvalue a1. Is it possible to measure the other eigenvalue a2 at a time t after the first measurement?

Could I write something like

\vert \psi(t)\rangle = e^{-i \hat H t / \hbar}\vert \psi(0) \rangle =e^{-i \hat H t / \hbar}\vert \nu_1 \rangle= e^{-i \hat H t / \hbar} \big(c_1\vert \nu_1 \rangle+c_2\vert \nu_2\rangle \big) =e^{-i E_1 t / \hbar} c_1\vert \nu_1 \rangle+e^{-i E_2 t / \hbar}c_2\vert \nu_{2}\rangle.
 
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You could measure a2 after the first measurement, but the equations in that last line are not quite right. You cannot expand ## | \nu_1 \rangle ## in terms of itself and ## | \nu_2 \rangle ##, because these vectors are linearly independent of each other. Instead, the time evolution operator could transform ## | \nu_1 \rangle ## into a different vector, which is itself expandable in terms of ## | \nu_1 \rangle ## and ## | \nu_2 \rangle ##. That is, you could have ## e^{-i\hat{H}t/ \hbar} | \nu_1 \rangle = c_1 | \nu_1 \rangle + c_2 | \nu_2 \rangle ##. Of course, this assumes that the two eigenstates form a basis, so that any state can be expanded in terms of them.
 
mangokiller said:
A ket is expanded as \vert \nu \rangle = c_1\vert \nu_1\rangle+c_2\vert \nu_{2}\rangle.

A measurement results in the eigenvalue a1. Is it possible to measure the other eigenvalue a2 at a time t after the first measurement?

It depends on what operator ##\vert \nu_1 \rangle## and ##\vert \nu_2 \rangle## are eigenstates of. If that operator commutes with the Hamiltonian, then the answer is no; if it does not, the answer is yes.

Even though the initial state would have been \vert \nu \rangle = c_1\vert \nu_1\rangle+c_2\vert \nu_{2}\rangle, after a measurement produces the result ##a_1## (and assuming that that's the eigenvalue associated with ##\vert \nu_1 \rangle##) the state is going to be ##\psi = \vert \nu_1 \rangle##, so that's the state that you want to be evolving forward in time.
 
Last edited:

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