Can this forum help me improve my word problem skills?

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Discussion Overview

The discussion centers around improving skills in solving word problems in mathematics. Participants share various word problems, explore different approaches to solving them, and engage in light-hearted commentary.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant expresses a desire to improve word problem skills and invites responses.
  • Another participant presents a solution to a word problem involving a man and a woman drinking a cask of wine, detailing the setup of ratios and calculations.
  • A different participant shares a similar word problem about two priests praying together, outlining their rates and the combined effort required.
  • Multiple participants reiterate the same word problems, providing their own calculations and methods for solving them, leading to slightly varied approaches and results.
  • Some posts include humorous or non-sequitur commentary that diverges from the main mathematical focus.

Areas of Agreement / Disagreement

Participants share various methods for solving the same word problems, but there is no consensus on a single approach or solution. Different interpretations and calculations are presented, indicating a lack of agreement on the best method.

Contextual Notes

Some participants reference previous discussions or solutions, but there are no clear resolutions to the problems posed. The conversation includes informal remarks that may distract from the mathematical content.

Who May Find This Useful

Individuals interested in enhancing their problem-solving skills in mathematics, particularly in word problems, may find the shared approaches and discussions beneficial.

nycmathdad
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I have decided to use this forum mainly to increase my word problems skills. Of course, I will make use of this forum for mathematics in general but word problems set up will be my main focus. I hope to see your reply.
 
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Beer soaked non sequitur ramblings follow.
nycmathdad said:
I ...
Spider marriage is complicated. Sometimes, you just got to mind your own biz.
 
jonah said:
Beer soaked non sequitur ramblings follow.

Spider marriage is complicated. Sometimes, you just got to mind your own biz.

I love the question in your signature. It seems like a simple ratio problem. If we set up each ratio as "Proportion of Cask" : "Days"

Man
1 : 20
1/20 : 1

Woman
1 : x
1/x : 1

Together
1/20 + 1/x : 1
(x + 20)/(20x) : 1
1 : (20x)/(x + 20)

But the Together ratio is 1 : 14, so

$\displaystyle \begin{align*} \frac{20\,x}{x + 20} &= 14 \\
20\,x &= 14 \left( x + 20 \right) \\
20\,x &= 14\,x + 280 \\
6\,x &= 280 \\
x &= 46\,\frac{2}{3} \end{align*}$

So it will take the woman 46 hours and 40 minutes to finish the cask on her own.
 
I think I did this before, but since Prove It brings it up:
" If one priest can pray a soul out of purgatory in 5 hours, while it takes a second priest 8 hours, how long will it take if the two priests pray together?"

So one priest prays at the rate of "one soul per 5 hours"" or "1/5 soul per hour" and the other at the rate of "one soul per eight hours" or "1/8 soul per hour". When they pray together, their rates add (I think that's stated in the bible) so 1/5+ 1/8= 8/40+ 5/40= 13/40". So it will require 40/13= 3 and 1/40 hour= 3 hours and 1.5 minutes.
 
Beer soaked ramblings follow.
Prove It said:
I love the question in your signature. It seems like a simple ratio problem. If we set up each ratio as "Proportion of Cask" : "Days"

Man
1 : 20
1/20 : 1

Woman
1 : x
1/x : 1

Together
1/20 + 1/x : 1
(x + 20)/(20x) : 1
1 : (20x)/(x + 20)

But the Together ratio is 1 : 14, so

$\displaystyle \begin{align*} \frac{20\,x}{x + 20} &= 14 \\
20\,x &= 14 \left( x + 20 \right) \\
20\,x &= 14\,x + 280 \\
6\,x &= 280 \\
x &= 46\,\frac{2}{3} \end{align*}$

So it will take the woman 46 hours and 40 minutes to finish the cask on her own.
Country Boy said:
I think I did this before, but since Prove It brings it up:
" If one priest can pray a soul out of purgatory in 5 hours, while it takes a second priest 8 hours, how long will it take if the two priests pray together?"

So one priest prays at the rate of "one soul per 5 hours"" or "1/5 soul per hour" and the other at the rate of "one soul per eight hours" or "1/8 soul per hour". When they pray together, their rates add (I think that's stated in the bible) so 1/5+ 1/8= 8/40+ 5/40= 13/40". So it will require 40/13= 3 and 1/40 hour= 3 hours and 1.5 minutes.
It amazes me that people who took the time to solve my two preposterous signature questions were able to control their laughter after seeing them for the first time.
Timios and Skipjack have also took a shot at them at
https://mathforums.com/goto/post?id=601053
Soroban at
Hello, jonah1!
A man drink a cask of wine in 20 days.
If his wife drinks with him, it take only 14 days.
How long does it take for the wife alone?
The man drinks the cask in 20 days.
In one day, he can drink $\frac{1}{20}$ of the cask.
. . In 14 days, he can drink $\frac{14}{20} \,=\,\frac{7}{10}$ of the cask.
The woman drinks the cask in $x$ days (alone).
In one day, she can drink $\frac{1}{x}$ of the cask.
. . In 14 days, she can drink $\frac{14}{x}$ of the cask.
Together, in 14 days, they can drink $\frac{7}{10} + \frac{14}{x}$ of the cask.
But we are told: together, in 14 days, they will drink the cask (one cask).
There is our equation! . . . $\frac{7}{10} + \frac{14}{x} \;=\;1$
Go for it!

Frick at
I have looked at these for so long, I just can't stand it any more:
A man can drink a cask of wine in 20 days, but if his wife drinks with him it will take only 14 days—how long would it take for the wife alone?
When two people, or machines, etc. do something together, their rates add. Let the number of days the wife would take to drink a caskof wine be "x". Then her rate is $\frac{1}{x}$ "days per cask. Her husband's rate is $\frac{1}{20}$ and their rate together is $\frac{1}{14}$. We have $\frac{1}{x}+ \frac{1}{20}= \frac{1}{14}$. Multiply by the least common multiple of the denominators, 140x.
$140+7x=10x$
$140=3x$
$x=\frac{140}{3}$.
It would take the wife, alone, 46 and 2/3 days to drink the cask of wine.(I shall start experimenting to see how long it will take me to drink a cask of wine!)
If one priest can pray a soul out of purgatory in 5 hours, while it takes a second priest 8 hours, how long will it take if the two priests pray together?
This is even simpler, almost an arithmetic problem. The first priest prays at the rate $\frac{1}{5}$ "soul per hour" and the second priest prays at the rate of $\frac{1}{8}$ "soul per hour". Together they pray at the rate of $\frac{1}{5}+ \frac{1}{8}=\frac{8}{40}+ \frac{5}{40}= \frac{13}{40}$ "soul per hour". Together it would take $\frac{40}{13}$ or 3 and 1/13 "hour per soul".
 
Last edited:
nycmathdad said:
I have decided to use this forum mainly to increase my word problems skills. Of course, I will make use of this forum for mathematics in general but word problems set up will be my main focus. I hope to see your reply.
Don't post your personal opinions in the Chat Room and you'll probably do just fine.

-Dan
 
topsquark said:
Don't post your personal opinions in the Chat Room and you'll probably do just fine.

-Dan

he’s already been banned …
 
skeeter said:
he’s already been banned …
Wow. I've been away for a while!

-Dan
 
I would be inclined to think that "pounds of word problems" would be enough!
 

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