Can Watercooling Solve My Noisy Computer Problem?

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Watercooling can effectively reduce computer noise by using a quieter fan at lower voltages, such as 7V instead of 12V, which decreases airflow and noise levels. The setup involves cooling two processors rated at 54.6W with a radiator capable of dissipating 790kcal/hour, which translates to approximately 919W. Calculations suggest that if the radiator can handle 900W, the airflow can be reduced while maintaining processor temperatures below 45°C. The discussion highlights the trade-off between noise and airflow, emphasizing the need for careful consideration of fan voltage adjustments. Overall, a well-designed watercooling system can significantly mitigate noise issues in high-performance computers.
jonnylane
Summer project: Watercooling a computer so it is a quiet as possible.

I have a computer case where the ambient air temperature is around 37’C and the room temperature is around 20’C.
I will be cooling two processors rated at 54.6W by piping water over them serially to a radiator which can dissipate upto 790kcal/hour providing there is an airflow of 100 cubic feet per minute.

This is quite easy to achieve, but that level of airflow creates about 60dB.

The plan is to use an ‘over-rated’ system and then have a fan powered at a lower voltage which should be quieter. It is straightforward to run the fan at 7v instead of 12v.

I have browsed around I have a pump which runs at 1200l/h. I will be using tubing with a diameter of 1/2inch.

My question is:
  • Is one radiator going to be enough to keep the processors below 45’C?
  • If a 12v fan makes 60dB moving 100cfm of air, what will happen when I run it at 7 or even 5v?

I appreciate it’s a little vague, just ask if you need more information :)
 
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If a 12v fan makes 60dB moving 100cfm of air, what will happen when I run it at 7 or even 5v?

well, it will make less noise, but it will also move less air. IMO.
 
I will be cooling two processors rated at 54.6W by piping water over them serially to a radiator which can dissipate upto 790kcal/hour providing there is an airflow of 100 cubic feet per minute.
so, I did some calculations and 790kcal/hour = (790000*4.19J)/(3600s) = 919W
you should check this anyway...
If the radiator can dissipate 900W and your processors give 54.6 W I guess you can lower the airflow a bit, by runnig the fan at 7V.
 
"Any sufficiently advanced bug is indistinguishable from a feature."

Whence: "If you can't fix it, feature it!"
 
Originally posted by HallsofIvy
"Any sufficiently advanced bug is indistinguishable from a feature."

Whence: "If you can't fix it, feature it!"

yep, but after you feature it you have to offer suport for that... :wink:
 
I do not have a good working knowledge of physics yet. I tried to piece this together but after researching this, I couldn’t figure out the correct laws of physics to combine to develop a formula to answer this question. Ex. 1 - A moving object impacts a static object at a constant velocity. Ex. 2 - A moving object impacts a static object at the same velocity but is accelerating at the moment of impact. Assuming the mass of the objects is the same and the velocity at the moment of impact...

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