Can You Crack the 14-Digit Number Puzzle?

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  • Thread starter Thread starter PRodQuanta
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SUMMARY

The discussion centers around solving a 14-digit number puzzle that begins with 4 and ends with 3, containing two of each digit from 1 to 7, with specific spacing requirements between identical digits. The solution proposed by Paden Roder involves multiplying the numbers 36825889 by 1253777. Participants are encouraged to share their methods, whether through mathematical formulas or trial and error approaches, to enhance understanding of the solution process.

PREREQUISITES
  • Understanding of combinatorial number theory
  • Familiarity with multiplication of large integers
  • Basic knowledge of digit placement constraints
  • Experience with problem-solving techniques in mathematics
NEXT STEPS
  • Research combinatorial mathematics for digit arrangement problems
  • Explore techniques for solving large integer multiplication
  • Study mathematical patterns in digit spacing and placement
  • Investigate trial and error methods in mathematical problem-solving
USEFUL FOR

Mathematicians, puzzle enthusiasts, educators teaching combinatorial concepts, and anyone interested in advanced problem-solving techniques.

PRodQuanta
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Well, I answered this question in a different forum in quite a hurry. So, if you can get it first, hurray for you.

Problem:
You have a 14 digit number. The number begins with 4 and ends with 3.

The trick:
the number has two of each numbers 1-7 in it. The 7's have 7 spaces between them. The 6's have six spaces in between them. The 5's have 5 spaces in between them. So on and so forth, down to the 1's have 1 space between them.

Ready...
Set...
GO!

Paden Roder
 
Mathematics news on Phys.org
Answer in white:

Multiply 36825889 by 1253777 to find the answer.
 
Eman...please explain how u got it
 
Correctomundo. Like rajesh said, IF you solved this using some mathematical formula, please do tell. If you are like me and just did the trial and error thing, there really is no explanation.

Others feel free to still answer the question.

Paden Roder
 

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