Can You Find the 8-Digit Number That is a Multiple of 2013 in Greg's Solution?

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$A=20\overline{abcd}13$ is an 8-digit number , and $A$ is a multiple of $2013$

please find $A$
 
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Albert said:
$A=20\overline{abcd}13$ is an 8-digit number , and $A$ is a multiple of $2013$

please find $A$

$$2013\times10001=20132013$$
 
greg1313 said:
$$2013\times10001=20132013$$
more than one solution
 
continuing with Greg's solution

A = 20132013 is one solution other solutions are A + 2013 *100 * n as long as 2013 * n < 10000 so n = 0 to 4 giving 20132013(this is A itself) , 20333313, 20534613,20735913, 20937213.