Can you move the sigma sign inside a sum?

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If I have a problem like
(N) sigma (K=0) Cos(Kpi)

can I just move the sigma sign inside the brackets? like

Cos(pi Sigma K)

just wondering because I have this on an assignment problem and we didn't learn it in class and the textbook doesn't cover it either. If I can move it inside the answer is easy so I am just assuming that's how to do it.

Also, how do you guys write all the math symbols, etc. I see them in other posts but I am pretty much useless on a computer so I have no idea how to do it.

Thanks
 
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No, you can't just move it inside. For example, consider:

[tex]\sum\limits_{k=1}^3 \cos(k\pi) = \cos(\pi) + \cos(2\pi) + \cos(3\pi)[/tex]

whereas

[tex]\cos(\pi \sum\limits_{k=1}^3 k) = \cos(\pi(1 + 2 + 3)) = \cos(6\pi)[/tex]

These are not the same thing.

(To see how the maths was displayed, click on the displayed equations.)
 
Yeah, I see what your saying. I tried it out after I posted. The problem is I don't have an end number to evaluate it at, but I have a formula for [tex]\sum\ limits_{K=0}^n K[/tex]. I'm thinking because there is no no number to evaluate it at that the answer is just a general formula, like n(n+1)/2 but our textbook desn't cover it and we didn't take it in class.
 
sorry about that mess with the sigma sign in the middle, I tried to edit it but it was going to delete it.

I guess it will take a little practice writting with that stuff.
 
If in doubt of sums, just write out the first terms of the sum in full.
Sometimes you can see where the sum is heading in infinity...

Greetz,
Leo
 
Well you know what you might be interested in this

[tex]\sum_{r = 0}^{n-1} \cos(\alpha + r\beta) = \cos(\alpha + \frac{n-1}{2}\beta) \frac{\sin(\frac{n\beta}{2})}{\sin(\frac{\beta}{2})}[/tex]

and you can prove this too :-)

For your problem, you'd first note that the angles are in arithmetic progression and the above expression would be used with

[tex]\alpha = 0[/tex]
[tex]\beta = \pi[/tex]

Cheers
Vivek