MHB Can You Prove $AB+BC \ge AD+DC$ in a Triangle?

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The discussion centers on proving the inequality $AB + BC \ge AD + DC$ within a triangle $\Delta ABC$ for a point $D$ inside it. Participants are encouraged to solve the problem within one hour and share their solving time alongside their solutions. The problem was proposed by Ackbach, and the community appreciates his contribution. Magneto successfully provided a correct solution, receiving acknowledgment for his effort. The thread highlights the collaborative nature of problem-solving in mathematics.
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This week's problem was submitted by Ackbach and we truly appreciate his taking the time to propose a quality problem for us to use as our Secondary School/High School POTW.:)Given a triangle $\Delta ABC$, and a point $D$ inside the triangle, prove that $AB+BC \ge AD+DC$. Here's the catch: see if you can prove it within one hour. Please post your honest solving time along with your solution. --------------------
Remember to read the http://www.mathhelpboards.com/showthread.php?772-Problem-of-the-Week-%28POTW%29-Procedure-and-Guidelines to find out how to http://www.mathhelpboards.com/forms.php?do=form&fid=2!
 
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Congratulations to magneto for his correct solution!:)

Solution from magneto:
Extend the line $AD$ to intersect $BC$; name that intersection $K$. Apply the triangle inequality on triangle $DKC$ and $AKB$, we have that $DC \leq DK + KC$ and $AK \leq AB + KB$. Thus,

$AD + DC \leq AD + DK + KC = AK + KC \leq AB + KB + KC = AB + BC$.

We'd like to express our thanks to Ackbach again for his suggested problem.:)
 
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