elimqiu
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Show that [itex]\displaystyle{\sum_{k=1}^{n-1}\sin\frac{km\pi}{n}\cot\frac{k\pi}{2n} = n-m}\quad\quad(m,n\in\mathbb{N}^+,\ m\le n)[/itex]
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The discussion revolves around proving the trigonometric identity \(\sum_{k=1}^{n-1}\sin\frac{km\pi}{n}\cot\frac{k\pi}{2n} = n-m\) for positive integers \(m\) and \(n\) with \(m \le n\). Participants explore various approaches to the proof, including the application of Euler's formula.
Participants express differing views on the applicability of Euler's formula and the context of the identity, indicating that multiple competing approaches and interpretations exist without a clear consensus.
Participants have not fully resolved the mathematical steps involved in the proof, and there are varying assumptions about the context in which the identity is applied.
micromass said:Why not start by applying the Euler formula
What do you get then??
elimqiu said:Show that [itex]\displaystyle{\sum_{k=1}^{n-1}\sin\frac{km\pi}{n}\cot\frac{k\pi}{2n} = n-m}\quad\quad(m,n\in\mathbb{N}^+,\ m\le n)[/itex]
It's a tool to proveberkeman said:What is the context of the question? Is it for schoolwork?