Can You Prove This Trigonometric Inequality?

Click For Summary

Discussion Overview

The discussion revolves around proving the trigonometric inequality $\tan 6^{\circ}+\tan 24^{\circ}+\tan 42^{\circ}+\tan 86^{\circ}\gt 4$. Participants share their approaches and solutions related to this inequality.

Discussion Character

  • Mathematical reasoning

Main Points Raised

  • One participant presents the inequality to be proven, stating it as a problem to solve.
  • Another participant reiterates the same inequality, indicating they have a solution to propose.
  • A subsequent post indicates that the participant has a solution but does not provide details in the quoted text.
  • A later reply acknowledges a correction made to the solution, thanking another participant for identifying mistakes.

Areas of Agreement / Disagreement

The discussion does not show clear consensus, as multiple participants are presenting their solutions and corrections without resolving the inequality or agreeing on a single approach.

Contextual Notes

There are indications of mistakes in the proposed solutions, but the specific nature of these mistakes and their implications remain unresolved.

anemone
Gold Member
MHB
POTW Director
Messages
3,851
Reaction score
115
Prove $\tan 6^{\circ}+\tan 24^{\circ}+\tan 42^{\circ}+\tan 86^{\circ}\gt 4$.
 
Mathematics news on Phys.org
anemone said:
Prove $\tan 6^{\circ}+\tan 24^{\circ}+\tan 42^{\circ}+\tan 86^{\circ}\gt 4$.

My solution:

First we know

[TABLE="class: grid, width: 700"]
[TR]
[TD]$\tan x=x+\dfrac{x^3}{3}+\dfrac{2x^5}{15}+\cdots$[/TD]
[TD]$86^{\circ}=\dfrac{86^{\circ}\pi}{180^{\circ}}>1.5$ rad[/TD]
[TD]$42^{\circ}=\dfrac{42^{\circ}\pi}{180^{\circ}}>0.733$ rad[/TD]
[/TR]
[/TABLE]

So we have

$\begin{align*}\tan 42^{\circ}+\tan 86^{\circ}&\gt (1.5+\dfrac{1.5^3}{3}+\dfrac{2(1.5)^5}{15}+\cdots)+(0.733+\cdots)\\&>3.6375+0.733\\&>4.3705\end{align*}$

Since $\tan 6^{\circ},\, \tan 24^{\circ}>0$ we can conclude by now $\tan 6^{\circ}+\tan 24^{\circ}+\tan 42^{\circ}+\tan 86^{\circ}\gt 4$ and we're hence done.
 
Last edited:
anemone said:
My solution:

First we know

[TABLE="class: grid, width: 700"]
[TR]
[TD]$\tan x=x+\dfrac{x^3}{3}+\dfrac{2x^5}{15}+\cdots$[/TD]
[TD]$86^{\circ}=\dfrac{86^{\circ}\pi}{180^{\circ}}<1.5$ rad[/TD]
[TD]$42^{\circ}=\dfrac{42^{\circ}\pi}{180^{\circ}}<0.733$ rad[/TD]
[/TR]
[/TABLE]

So we have

$\begin{align*}\tan 42^{\circ}+\tan 86^{\circ}&\gt (1.5+\dfrac{1.5^3}{3}+\dfrac{2(1.5)^5}{15}+\cdots)+(0.733+\cdots)\\&>3.6375+0.733\\&>4.3705\end{align*}$

Since $\tan 6^{\circ},\, \tan 24^{\circ}>0$ we can conclude by now $\tan 6^{\circ}+\tan 24^{\circ}+\tan 42^{\circ}+\tan 86^{\circ}\gt 4$ and we're hence done.

should be

$86^{\circ}=\dfrac{86^{\circ}\pi}{180^{\circ}}>1.5$ rad
 
Thanks kaliprasad for catching it, I just fixed the mistakes.:o
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K